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2 years ago

6

A grocery store has 5 pounds of granola. One customer buys 2/3 pound of granola and another buys 5/6 pound. After these purchase

s, how much granola is left?

1 answer:

Allushta [10]2 years ago

7 0

There are .55 pounds left.

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The total dinner bill for five persons at a restaurant was $203.25. What was the average cost per person in dollars ?

Norma-Jean [14]

Hello! To find the average of something, multiply the total of something by the number of units. In this case, we divide the total bill by 5 people to get the average cost per person. 203.25/5 is 40.65. There. The average cost of dinner per person was $40.65.

7 0

2 years ago

In how many ways can you spell the word ROOM in the grid below? You can start on any letter R, then on each step you can step on

Zina [86]

Answer:

84? Not sure but pretty sure

Step-by-step explanation:

In a straight line, the word can only be spelled on the diagonals, and there are only two diagonals in each direction that have 2 O's.

If 90° and reflex turns are allowed, then the number substantially increases.

Corner R: can only go to the adjacent diagonal O, and from there to one other O, then to any of the 3 M's, for a total of 3 paths.

2nd R from the left: can go to either of two O's, one of which is the same corner O as above. So it has the same 3 paths. The center O can go to any of 4 Os that are adjacent to an M, for a total of 10 more paths. That's 13 paths from the 2nd R.

Middle R can go the three O's on the adjacent row, so can access the three paths available from each corner O along with the 10 paths available from the center O, for a total of 16 paths.

Then paths accessible from the top row of R's are 3 +10 +16 +10 +3 = 42 paths. There are two such rows of R's so a total of 84 paths.

6 0

2 years ago

Read 2 more answers

Mrrafil [7]

Answer:

£510

Step-by-step explanation:

Simple interest = (principal × rate × time) / 100

Principal = £1700

Rate = 10%

Time = 3 years

Simple interest = (principal × rate × time) / 100

= (1700 × 10 × 3) / 100

= 51,000/100

= 510

Simple interest = £510

7 0

2 years ago

PLS ANSWER ASAP 30 POINTS!!! CHECK PHOTO! WILL MARK BRAINLIEST TO WHO ANSWERS

Sveta_85 [38]

I'll do Problem 8 to get you started

a = 4 and c = 7 are the two given sides

Use these values in the pythagorean theorem to find side b

$a^2 + b^2 = c^2\\\\4^2 + b^2 = 7^2\\\\16 + b^2 = 49\\\\b^2 = 49 - 16\\\\b^2 = 33\\\\b = \sqrt{33}\\\\$

With respect to reference angle A, we have:

opposite side = a = 4
adjacent side = b = $\sqrt{33}$
hypotenuse = c = 7

Now let's compute the 6 trig ratios for the angle A.

We'll start with the sine ratio which is opposite over hypotenuse.

$\sin(\text{angle}) = \frac{\text{opposite}}{\text{hypotenuse}}\\\\\sin(A) = \frac{a}{c}\\\\\sin(A) = \frac{4}{7}\\\\$

Then cosine which is adjacent over hypotenuse

$\cos(\text{angle}) = \frac{\text{adjacent}}{\text{hypotenuse}}\\\\\cos(A) = \frac{b}{c}\\\\\cos(A) = \frac{\sqrt{33}}{7}\\\\$

Tangent is the ratio of opposite over adjacent

$\tan(\text{angle}) = \frac{\text{opposite}}{\text{adjacent}}\\\\\tan(A) = \frac{a}{b}\\\\\tan(A) = \frac{4}{\sqrt{33}}\\\\\tan(A) = \frac{4\sqrt{33}}{\sqrt{33}*\sqrt{33}}\\\\\tan(A) = \frac{4\sqrt{33}}{(\sqrt{33})^2}\\\\\tan(A) = \frac{4\sqrt{33}}{33}\\\\$

Rationalizing the denominator may be optional, so I would ask your teacher for clarification.

So far we've taken care of 3 trig functions. The remaining 3 are reciprocals of the ones mentioned so far.

cosecant, abbreviated as csc, is the reciprocal of sine
secant, abbreviated as sec, is the reciprocal of cosine
cotangent, abbreviated as cot, is the reciprocal of tangent

So we'll flip the fraction of each like so:

$\csc(\text{angle}) = \frac{\text{hypotenuse}}{\text{opposite}} \ \text{ ... reciprocal of sine}\\\\\csc(A) = \frac{c}{a}\\\\\csc(A) = \frac{7}{4}\\\\\sec(\text{angle}) = \frac{\text{hypotenuse}}{\text{adjacent}} \ \text{ ... reciprocal of cosine}\\\\\sec(A) = \frac{c}{b}\\\\\sec(A) = \frac{7}{\sqrt{33}} = \frac{7\sqrt{33}}{33}\\\\\cot(\text{angle}) = \frac{\text{adjacent}}{\text{opposite}} \ \text{ ... reciprocal of tangent}\\\\\cot(A) = \frac{b}{a}\\\\\cot(A) = \frac{\sqrt{33}}{4}\\\\$

------------------------------------------------------

Summary:

The missing side is $b = \sqrt{33}$

The 6 trig functions have these results

$\sin(A) = \frac{4}{7}\\\\\cos(A) = \frac{\sqrt{33}}{7}\\\\\tan(A) = \frac{4}{\sqrt{33}} = \frac{4\sqrt{33}}{33}\\\\\csc(A) = \frac{7}{4}\\\\\sec(A) = \frac{7}{\sqrt{33}} = \frac{7\sqrt{33}}{33}\\\\\cot(A) = \frac{\sqrt{33}}{4}\\\\$

Rationalizing the denominator may be optional, but I would ask your teacher to be sure.

7 0

1 year ago

Consider a circle whose size can vary. Let r represent the radius of the circle (in cm) and let C represent the circumference of

Firdavs [7]

Answer:

$g (15)$ represents the radius (in cm) of a circle whose circumference is 15 cm

if $g (a) = 15$ , then a represents the circumference (in cm) of a circle whose radius is 15cm

Step-by-step explanation:

In a circle the following relationship can be posed:

$C = 2 \pi r$

Let g be a function that determines the radius of the circle from the value of its circumference, so, you have:

$g (C) =\frac{C}{2\pi}$

Thus, $g (15)$ represents the radius (in cm) of a circle whose circumference is 15 cm. You have to $g (15) =\frac{15}{2\pi}$ .

On the other hand, if $g (a) = 15$ , then $a$ represents the circumference (in cm) of a circle whose radius is 15cm. You have to $a=2 \pi(15) = 30 \pi$

4 0

2 years ago