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ANTONII [103]
3 years ago
10

Find the sum of the squared residuals for each potential line of fit, and then determine which potential line is the true line o

f best fit. Equation 1 Square of residual .28 .167 .19 Equation 2 Square of residual .005 .110 .09 Equation 3 Square of residual .125 .125 .26 Equation 4 Square of residual .212 .009 .08 options: Equation 4 Equation 2 Equation 1 Equation 3
Mathematics
1 answer:
Paul [167]3 years ago
3 0

Answer:

.163

Step-by-step explanation:

not sure what so ever that is a hard question

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Please help with this Piecewise problem!!
tino4ka555 [31]

Remark

That was well worth doing. Desmos gave you the answer to the graph. Unfortunately I can only give you the correct graph. You will have to figure out from the choices which one is the correct answer -- or edit it so I can see what the rest of the question is.

Graph

The red one is f(x) is x + 3 {x <= -2}

The blue one is f(x) is x^2 - 1 {-2 <x <1} Notice the gap at 2. It is not continuous

The green one is f(x) is log_2(-x + 3)  {1 <=x < 3} and there is a gap between the blue and green one.

4 0
3 years ago
Please help me out with this Algebra 1 question
Zarrin [17]

Answer:

linear

Step-by-step explanation:

it would be linear because there is a constant rate of change

3 0
3 years ago
Read 2 more answers
Can someone help me with this thank you
levacccp [35]

Answer:

B

Step-by-step explanation:

This quadratic factors.

x^2 - 15x + 56

= (x - 7)(x - 8)

x - 7 = 0

x = 7

=====

x - 8 = 0

x = 8

====

{7,8}

5 0
3 years ago
According to a study conducted by the Gallup Organization, the the proportion of Americans who are afraid to fly is 0.10. A rand
notsponge [240]

Answer: 0.1457

Step-by-step explanation:

Let p be the population proportion.

Given: The proportion of Americans who are afraid to fly is 0.10.

i.e. p= 0.10

Sample size : n= 1100

Sample proportion of Americans who are afraid to fly =\hat{p}=\dfrac{121}{1100}=0.11

We assume that the population is normally distributed

Now, the probability that the sample proportion is more than 0.11:

P(\hat{p}>0.11)=P(\dfrac{\hat{p}-p}{\sqrt{\dfrac{p(1-p)}{n}}}>\dfrac{0.11-0.10}{\sqrt{\dfrac{0.10(0.90)}{1100}}})\\\\=P(z>\dfrac{0.01}{0.0090453})\ \ \ [\because z=\dfrac{\hat{p}-p}{\sqrt{\dfrac{p(1-p)}{n}}} ]\\\\=P(z>1.1055)\\\\=1-P(z\leq1.055)\\\\=1-0.8543=0.1457\ \ \ [\text{using z-table}]

Hence, the probability that the sample proportion is more than 0.11 = 0.1457

3 0
3 years ago
Two times the greater of two consecutive integers is 9 less than three times the lesser integer. What are the integers?
lara [203]

Answer:

11 and 12

Step-by-step explanation:

x=smaller

y=larger

2y=3x-9    x+1=y

2(x+1)=3x-9

2x+2=3x-9

11=x

                11+1=y

                    12=y

3 0
3 years ago
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