Which expression can be used to convert 22 Australian dollars to US dollars?

6. Which of the following fractions is equivalent to

hichkok12 [17]

Answer:

D

Step-by-step explanation:

5 0

3 years ago

Which of the following sets are subspaces of R3 ?

Ratling [72]

Answer:

The following are the solution to the given points:

Step-by-step explanation:

for point A:

$\to A={(x,y,z)|3x+8y-5z=2} \\\\\to for(x_1, y_1, z_1),(x_2, y_2, z_2) \varepsilon A\\\\ a(x_1, y_1, z_1)+b(x_2, y_2, z_2) = (ax_1+bx_2,ay_1+by_2,az_1+bz_2)$

$=3(aX_l +bX_2) + 8(ay_1 + by_2) — 5(az_1+bz_2)\\\\=a(3X_l+8y_1- 5z_1)+b (3X_2+8y_2—5z_2)\\\\=2(a+b)$

The set A is not part of the subspace $R^3$

for point B:

$\to B={(x,y,z)|-4x-9y+7z=0}\\\\\to for(x_1,y_1,z_1),(x_2, y_2, z_2) \varepsilon B \\\\\to a(x_1, y_1, z_1)+b(x_2, y_2, z_2) = (ax_1+bx_2,ay_1+by_2,az_1+bz_2)$

$=-4(aX_l +bX_2) -9(ay_1 + by_2) +7(az_1+bz_2)\\\\=a(-4X_l-9y_1+7z_1)+b (-4X_2-9y_2+7z_2)\\\\=0$

$\to a(x_1,y_1,z_1)+b(x_2, y_2, z_2) \varepsilon B$

The set B is part of the subspace $R^3$

for point C: $\to C={(x,y,z)|x$

In this, the scalar multiplication can't behold

$\to for (-2,-1,2) \varepsilon C$

$\to -1(-2,-1,2)= (2,1,-1)$ ∉ C

this inequality is not hold

The set C is not a part of the subspace $R^3$

for point D:

$\to D={(-4,y,z)|\ y,\ z \ arbitrary \ numbers)$

The scalar multiplication s is not to hold

$\to for (-4, 1,2)\varepsilon D\\\\\to -1(-4,1,2) = (4,-1,-2)$ ∉ D

this is an inequality, which is not hold

The set D is not part of the subspace $R^3$

For point E:

$\to E= {(x,0,0)}|x \ is \ arbitrary) \\\\\to for (x_1,0 ,0) ,(x_{2},0 ,0) \varepsilon E \\\\\to a(x_1,0,0) +b(x_{2},0,0)= (ax_1+bx_2,0,0)\\$

The $x_1, x_2$ is the arbitrary, in which $ax_1+bx_2$ is arbitrary

$\to a(x_1,0,0)+b(x_2,0,0) \varepsilon E$

The set E is the part of the subspace $R^3$

For point F:

$\to F= {(-2x,-3x,-8x)}|x \ is \ arbitrary) \\\\\to for (-2x_1,-3x_1,-8x_1),(-2x_2,-3x_2,-8x_2)\varepsilon F \\\\\to a(-2x_1,-3x_1,-8x_1) +b(-2x_1,-3x_1,-8x_1)= (-2(ax_1+bx_2),-3(ax_1+bx_2),-8(ax_1+bx_2))$

The $x_1, x_2$ arbitrary so, they have $ax_1+bx_2$ as the arbitrary $\to a(-2x_1,-3x_1,-8x_1)+b(-2x_2,-3x_2,-8x_2) \varepsilon F$

The set F is the subspace of $R^3$

5 0

3 years ago

12 + 30x<br><br> neeeeeeeeed heeeeeeeeeeeelp

deff fn [24]

Answer:42x

Step-by-step explanation:

4 0

2 years ago

Read 2 more answers

If a customer ordered 5 items and the order had a total of 17 wheels, how many wagons were odered?

Nimfa-mama [501]

If a customer ordered 5 items and the order had a total of 17 wheels, we are to determine the number of wagons that was ordered. A wagon has four wheels, therefore, 17 divided by 4 wheels is equal to 4 r. 1. So, 4 wagons were ordered and one extra wheel to complete the 17 wheels and 5 orders.

6 0

3 years ago

Read 2 more answers

URGENT PLEASE HELP !!!!!

Mumz [18]

Answer:

Let P represent the number of pies sold and J represent the number of juices sold.

a)

The first equation for the sum of the sales:

P + J = 79

P = 79 - J

Next, for the sum of the amounts earned:

1.65P + 1.36J = 118.17

Substituting P,

1.65 (79 - J) + 1.36J = 118.17

J = 42

Using this value of J,

P = 79 - 42

P = 37

b)

Mr. Sanchez's class earned: 1.65 x 37 = $61.05

Mr. Kelly's class earned: 1.36 x 42 = $57.12

So Mr. Sanchez's class earned more money.

c) Mr. Sanchez's class earned:

61.05 - 57.12

= $3.93 more than Mr. Kelly's class

Step-by-step explanation:

:)

4 0

3 years ago