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EastWind [94]
3 years ago
7

What does B equal in the equation b=y+1.3x

Mathematics
1 answer:
lubasha [3.4K]3 years ago
3 0
The root is = ( -13/10 , 0 ) and the domain is = yer
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5x − 3+ 2x = x + 7 + 6x
Masteriza [31]

Answer:

There isnt any solution.

Step-by-step explanation:

but these are the steps:

Step 1: Simplify both sides of the equation.

5x−3+2x=x+7+6x

5x+−3+2x=x+7+6x

(5x+2x)+(−3)=(x+6x)+(7)

7x+−3=7x+7

7x−3=7x+7

Step 2: Subtract 7x from both sides.

7x−3−7x=7x+7−7x

−3=7

Step 3: Add 3 to both sides.

−3+3=7+3

0=10

<h3>hope this helps</h3>

7 0
4 years ago
Jennifer is buying party supplies. She is planning on buying twice as many balloons as noisemakers. The number of napkins Jennif
pishuonlain [190]

Answer:

808 over 25 as a faraction

Step-by-step explanation

a quarter of 65 is 16 4 over 25

16 4 over 25 times 2 808 over 25 as a fraction

4 0
3 years ago
The circumference of a circle of latitude is two thirds of the circumference of the equator. what is the latitude?
ss7ja [257]
Assuming a spherical Earth, the circumference varies as the cosine of the latitude. Your latitude is
  arccos(2/3) ≈ 48.1897° ≈ 48° 11' 22.9"

_____
North or South, it doesn't matter.
7 0
3 years ago
What are the solutions to he quadratic equation 3x^2+15-18=0
kozerog [31]

3 {x}^{2}  + 15 - 18 = 0 \\  {3x}^{2}  - 3 = 0 \\  {x}^{2}  - 1 = 0 \\  {x}^{2}  = 1
either x= +1
or x= -1
8 0
3 years ago
(x+7)/(x^2-49) find the domain. show work
harina [27]
\large\begin{array}{l} \textsf{Find the domain of}\\\\ \mathsf{f(x)=\dfrac{x+7}{x^2-49}}\\\\ \mathsf{f(x)=\dfrac{x+7}{x^2-7^2}}\\\\\\ \textsf{Factor out the denominator using special products:}\\\\ \textsf{(a difference of squares)}\\\\ \mathsf{f(x)=\dfrac{x+7}{(x+7)(x-7)}} \end{array}


\large\begin{array}{l} \textsf{Restrictions for the domain:}\\\\ \bullet~~\textsf{Denominators must not be zero:}\\\\ \mathsf{(x+7)(x-7)\ne 0}\\\\ \begin{array}{rcl} \mathsf{x+7\ne 0}&~\textsf{ and }~&\mathsf{x-7\ne 0}\\\\ \mathsf{x\ne -7}&~\textsf{ and }~&\mathsf{x\ne 7} \end{array} \end{array}


\large\begin{array}{l} \textsf{Therefore, the domain of f is}\\\\ \mathsf{D_f=\{x\in\mathbb{R}:~~x\ne -7~~and~~x\ne 7\}}\\\\\\ \textsf{or using a more compact form}\\\\ \mathsf{D_f=\mathbb{R}\setminus\{-7,\,7\}}\\\\\\ \textsf{or using the interval notation}\\\\ \mathsf{D_f=\left]-\infty,\,-7\right[\,\cup\,\left]7,\,+\infty\right[.} \end{array}


<span>If you're having problems understanding this answer, try seeing it through your browser: brainly.com/question/2155752


\large\textsf{I hope it helps. :-)}



Tags: <em>function domain real rational factorizing special product interval</em>

</span>
7 0
3 years ago
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