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Sloan [31]
3 years ago
13

1)In a sample of 100 households, the mean number of hours spent on social networking sites during the month of January was 50 ho

urs. In a much larger study,
the standard deviation was determined to be 6 hours.
Assume the population standard deviation is the same. What is the 98% confidence interval for the mean hours devoted to social networking in January?

2)Two studies were completed in Florida. One study in northern Florida involved 2,000 patients; 64% of them experienced flu-like symptoms during the month of December.
The other study, in southern Florida, involved 3,000 patients;
54% of them experienced flu-like symptoms during the same month. Which study has the smallest margin of error for a 95% confidence interval?
Mathematics
1 answer:
ra1l [238]3 years ago
8 0
So the following is the answer of the following question in your problem and please do not post to many question in just one posting. 
#1 The 98% confidence interval for the mean hours is between 6 and 50.
#2 The smallest margin of error between the two is southern florida with 1.8% margin of error.
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2 years ago
X + y = 24
Masja [62]

Answer:

(10, 14)

Step-by-step explanation:

To solve this system let's use substitution:

Solve the first equation for x, obtaining x = 24 - y, and then substitute 24 - y for x in the second equation:

3(24 - y) + 5y = 100

Performing the indicated multiplication, we get:

72 - 3y + 5y = 100

Combining like terms results in 72 - 100 = -2y, or -28 = -2y

Thus, y must be 14.

If y = 14, then the first equation tells us that x = 10.

Check:  Is this true?  3(10) + 5(14) = 100  YES

The solution is (10, 14).

What was it about the questions on the best that you were supposed to compare to this solution?

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3 years ago
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Step-by-step explanation:

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Write an equation in standard form of a quadratic function that has x-intercepts -2 and 5 and k=-4
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Step-by-step explanation:

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