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Sloan [31]
3 years ago
13

1)In a sample of 100 households, the mean number of hours spent on social networking sites during the month of January was 50 ho

urs. In a much larger study,
the standard deviation was determined to be 6 hours.
Assume the population standard deviation is the same. What is the 98% confidence interval for the mean hours devoted to social networking in January?

2)Two studies were completed in Florida. One study in northern Florida involved 2,000 patients; 64% of them experienced flu-like symptoms during the month of December.
The other study, in southern Florida, involved 3,000 patients;
54% of them experienced flu-like symptoms during the same month. Which study has the smallest margin of error for a 95% confidence interval?
Mathematics
1 answer:
ra1l [238]3 years ago
8 0
So the following is the answer of the following question in your problem and please do not post to many question in just one posting. 
#1 The 98% confidence interval for the mean hours is between 6 and 50.
#2 The smallest margin of error between the two is southern florida with 1.8% margin of error.
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53.02 in expanded notation
svet-max [94.6K]
<span>53.02 in expanded notation</span> would be 25*2 + 3 + 0.3
3 0
3 years ago
Read 2 more answers
1) Solve the system by elimination?
lesya692 [45]

Answer:

1) (-6,-9)

times the top equation buy -4 so you cancel out the y

so it be -8x+4y=12 no cancel out the y's

so it be -8x=12 and 5x=6

now combined like terms to get -3x= 36

x = -6 now go plug that back in one of the equations to get y

y = -9

2) (-2,-5)

now on this one you going to substitute y= (2x-1) for y in the otheir eqaution

so it look like 3x-(2x-1)=-1

do your combining of like terms and your division & you get x = -2

now plug x in to y=2x-1 to get y = -5

6 0
3 years ago
Plz help with this question.
Galina-37 [17]

Answer:

Both \:  the \:  moon  \: and  \: earth  \: are  \: in \:  \\  the  \: shape \:  of  \: spheres. \\ Surface\: area  \: of \:  a \: sphere  \: of  \: radius \:  'r' \\

Let d1 be the diameter of the moon and d2 and be the diameter of the earth.Let r1 be the radius of the moon and r2 be the radius of the earth.

given \: d1 =  \frac{1}{4}d2 \\ = > 2r1 =  \frac{1}{4} ×2r2  \\  =>r1 =  \frac{1}{4}×r2 \\ Now,  \: ratio \:  of \:  \:  their  \: surface \:  areas \:  is:  \\ =  s1: s2 \\  = r {1}^{2}: r {2}^{2} \\ = {1}^{2 } : {4}^{2 } \\ =1:16

<h2> hope it helps you</h2>
7 0
2 years ago
Read 2 more answers
Find the amount paid for the loan.<br><br> $2000 at 12% for 3 years
Free_Kalibri [48]
They paid $720

Here's why:
The formula to this is Interest = Principal x Rate x Time or i = prt
Principal = $2000
Rate = 12%
Time = 3 years
2000 x .12 x 3 = i PEMDAS
2000 x .12 = 240
240 x 3 = 720
i = $720
3 0
3 years ago
On a biased dice the probability of getting 1 is 0.3. The ice is rolled 150 times. How many ones would you expect to roll?
Montano1993 [528]

Answer:  45

=====================================================

Work Shown:

n = number of rolls = 150

p = probability of rolling a "1" = 0.3

n*p = expected number of "1"s that show up out of the 150 rolls

n*p = 150*0.3

n*p = 45

We expect about 45 ones will show up.

8 0
2 years ago
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