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natulia [17]
3 years ago
10

What is the median of the data set represented by the dot plot?

Mathematics
2 answers:
podryga [215]3 years ago
7 0

Answer:

<h2><u>5</u></h2>

Step-by-step explanation:

Median - The middle number in a set a data

First, you need to list the numbers least, on the left, to greatest, on the right.

3, 3, 4, 5, 5, 5, 6, 8, 8

Once you have done this, you can follow these steps.

Cross off the lowest number. Cross off the highest number. Repeat until there is one or two numbers left.

3, 4, 5, 5, 5, 6, 8

4, 5, 5, 5, 6

5, 5, 5

5

Since there is one number left, that is the median. In case of there being two numbers left, you add them together. Then divide by 2 and that would be your median

Ipatiy [6.2K]3 years ago
6 0

Answer:

\Large \boxed{\sf 5}

Step-by-step explanation:

Data set is 3, 3, 4, 5, 5, 5, 6, 8, 8

Median is the middle value in a data set

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I need help with this ! ❤️
Arada [10]

Answer:

The correct answer is: (x,y)↦(x+ 8 ,y+ 16)

Hoped I helped

6 0
3 years ago
12-4+5 x 2 = 20<br>Where The parentheses should go?​
Vinvika [58]

The value of x is √2.5

<h3>How to solve arithmetic?</h3>

Arithmetic can be solved by using PEMDAS rule.

P = parenthesis

E = exponential

M = Multiplication

D = division

A = addition

S = Subtraction

Therefore,

12 - 4 + 5x² = 20

12 - 4 +  5x² = 20

8 + 5x² = 20

5x² = 20 - 8

5x² = 12

x² = 12 / 5

x = √2.4

learn more on arithmetic here: brainly.com/question/2880880

#SPJ1

8 0
1 year ago
A jogger ran 3 miles due east of his house. then he ran 5 miles at a heading of 30o east of north (or 30o ne). how far is he fro
Natasha_Volkova [10]

Magnitude of the net displacement: 7.0 miles

Step-by-step explanation:

In order to find the total displacement of the man, we have to resolve each displacement along the x- and y- direction.

Taking x as positive x direction and y as positive north direction:

- The first motion is 3 miles due east, so

A_x = 3 mi\\A_y = 0

- The second motion is 5 miles at 30^{\circ} east of north, so:

B_x = 5 sin 30^{\circ}=2.5 mi\\B_y = 5 cos 30^{\circ}=4.3 mi

So the components of the net displacement are

R_x = A_x + B_x = 3 + 2.5 = 5.5 mi\\R_y = A_y+B_y = 0 + 4.3 = 4.3 mi

And so the magnitude of the net displacement is

d=\sqrt{R_x^2+R_y^2}=\sqrt{5.5^2+4.3^2}=7.0 mi

So, he is 7.0 miles far from the house.

Learn more about distance and displacement:

brainly.com/question/3969582

#LearnwithBrainly

4 0
3 years ago
A sign made of solid wood is in the shape of a pyramid. The base is a triangle with a base of 6 feet and a height of 4 feet. The
zaharov [31]

Answer:

$144

Step-by-step explanation:

Volume of the pyramid = 1/3BH

Base area B = 1/2 * 6 * 4

Base area B = 12 ft²

Height H = 4ft

Volume of the pyramid = 12 * 4

Volume of the pyramid = 48ft³

SInce 1 ft³ = $3

48ft³ = x

Cross multiply

x = 3 * 48

x = 144

Hence the cost of the sign is $144

5 0
2 years ago
A particle is projected with a velocity of <img src="https://tex.z-dn.net/?f=40ms%5E-%5E1" id="TexFormula1" title="40ms^-^1" alt
Katena32 [7]

Answer:

2\sqrt{55}\text{ m/s or }\approx 14.8\text{m/s}

Step-by-step explanation:

The vertical component of the initial launch can be found using basic trigonometry. In any right triangle, the sine of an angle is equal to its opposite side divided by the hypotenuse. Let the vertical component at launch be y. The magnitude of 40\text{ m/s} will be the hypotenuse, and the relevant angle is the angle to the horizontal at launch. Since we're given that the angle of elevation is 60^{\circ}, we have:

\sin 60^{\circ}=\frac{y}{40},\\y=40\sin 60^{\circ},\\y=20\sqrt{3}(Recall that \sin 60^{\circ}=\frac{\sqrt{3}}{2})

Now that we've found the vertical component of the velocity and launch, we can use kinematics equation v_f^2=v_i^2+2a\Delta y to solve this problem, where v_f/v_i is final and initial velocity, respectively, a is acceleration, and \Delta y is distance travelled. The only acceleration is acceleration due to gravity, which is approximately 9.8\:\mathrm{m/s^2}. However, since the projectile is moving up and gravity is pulling down, acceleration should be negative, represent the direction of the acceleration.

What we know:

  • v_i=20\sqrt{3}\text{ m/s}
  • a=-9.8\:\mathrm{m/s^2}
  • \Delta y =50\text{ m}

Solving for v_f:

v_f^2=(20\sqrt{3})^2+2(-9.8)(50),\\v_f^2=1200-980,\\v_f^2=220,\\v_f=\sqrt{220}=\boxed{2\sqrt{55}\text{ m/s}}

3 0
3 years ago
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