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Pani-rosa [81]
3 years ago
9

If the rate of decrease for the partial pressure of N2H4N2H4 in a closed reaction vessel is 70 torr/htorr/h , what is the rate o

f change for the partial pressure of NH3NH3 in the same vessel
Chemistry
1 answer:
german3 years ago
7 0

Answer:

r_{NH_3}=140torr/h

Explanation:

Hello,

In this case, the undergoing chemical reaction is:

N_2H_4 (g) + H_2 (g) \rightarrow 2 NH_3

Thus, in terms of pressures, the rate becomes:

-r_{N_2H_4}=\frac{1}{2} r_{NH_3}

Thus, the rate of change for the partial pressure of ammonia turns out:

r_{NH_3}=2*(-r_{N_2H_4})\\r_{NH_3}=2*[-(-70torr/h)]\\r_{NH_3}=140torr/h

The rate of decrease of partial pressure of urea is taken negative as it is a reactant whereas ammonia a product which has 2 as its stoichiometric coefficient.

Best regards.

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