Question

Simon has more money than Kande. if Simon gave Kande K20, they would have the same amount. While if Kande gave Simon $22, Simon would then have twice as much as Kande. How much does each one actually have?​

Answer 1

Given parameters;

  Let us solve this problem step by step;

Let us represent Simon's money by S

Kande's money by K

• Simon has more money than Kande

               S > K

•  if Simon gave Kande K20, they would have the same amount;

 if Simon gives $20, his money will be  S - 20 lesser;

      When Kande receives $20, his money will increase to K + 20

                     S - 20  = K + 20   ------ (i)

• While if Kande gave Simon $22, Simon would then have twice as much as Kande;

          if Kande gave Simon $22, his money will be K - 22

    Simon's money, S + 22;

                  S + 22  = 2(K - 22)    ------ (ii)

Now we have set up two equations, let us solve;

         S - 20  = K + 20  ---- i

         S + 22  = 2(K - 22)  ;       S + 22  = 2K - 44  ---- ii

So,      S - 20  = K + 20

          S + 22  = 2K - 44

subtract both equations;

               -20 - 22  = (k -2k)  + 64

                   -42  = -k + 64

                       k  = 106

Using equation i, let us find S;

            S - 20 = K + 20

             S - 20  = 106 + 20

              S = 106 + 20 + 20  = 146

Therefore, Kande has $106 and Simon has $146