3 years ago

What is the sum of 3b(b-4) and 6(b-8)?

Mathematics

2 answers:

polet [3.4K]3 years ago

6 0

Answer:

3b² -6b -48

Step-by-step explanation:

Given : 3b(b-4) and 6(b-8).

To find : What is the sum.

Solution : We have given 3b(b-4) and 6(b-8).

According to question :

3b(b-4) + 6(b-8).

Distribute 3b over b-4 and 6 over b-8.

3b² -12b + 6b -48.

Combine like terms.

3b² -6b -48.

Therefore,3b² -6b -48.

dezoksy [38]3 years ago

4 0

3b^2 - 6b +36.

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