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Korvikt [17]
3 years ago
14

Read this passage from Steinbeck's "The Chrysanthemums": There was a little square sandy bed kept for rooting the chrysanthemums

. With her trowel she turned the soil over and over, and smoothed it and patted it firm. Then she dug ten parallel trenches to receive the sets. Back at the chrysanthemum bed she pulled out the little crisp shoots, trimmed off the leaves of each one with her scissors and laid it on a small orderly pile. What does the appearance of the garden reveal about Elisa's character? A. Elisa is upset that the flower-growing season is coming to an end. B. Elisa is tired of growing chrysanthemums and wants to try something new. C. Elisa is angry about the fact that Henry won't let her have a bigger garden. D. Elisa takes great care of the things she loves, like her garden.
English
2 answers:
fiasKO [112]3 years ago
8 0

D. Elisa takes great care of the things she loves, like her garden. because she care and you can tell as you read the story

Mademuasel [1]3 years ago
3 0
D. Elisa takes great care of the things she loves, like her garden.  She dug trenches, trimmed off the leaves of each one, and laid them in an orderly pile.  
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Answer:

Explanation:

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Looking down instead of looking people in the eye.

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★ Formula Applied :

\begin{gathered}\sf \bullet\ \; cos^2x-sin^2x=cos2x\\\\\to\ \sf \pink{sin^2x-cos^2x=-cos2x}\end{gathered}

\begin{gathered}\bullet\ \; \sf sin2x=2.sinx.cosx\\\\\to \sf \blue{sinx.cosx=\dfrac{sin2x}{2}}\end{gathered}

\displaystyle \bullet\ \; \sf \int \dfrac{dx}{x}

\bullet\ \; \sf \ln (ab)=\ln a+\ln

★ Explanation :

\begin{gathered}\displaystyle \sf \int \dfrac{sin^2x-cos^2x}{sinx.cosx}dx\\\\\to \sf \int \dfrac{-cos2x}{\frac{sin2x}{2}}dx\\\\\to \sf \int \dfrac{-2cos2x}{sin2x}dx\end{gathered}

Lets use substitution method ,

Let , u = sin2x

⇒ du = 2.cos2x.dx

\begin{gathered}\to \displaystyle \sf \int \dfrac{-du}{u}\\\\\to \sf -\int \dfrac{du}{u}\\\\\to \sf -ln|u|\\\\\end{gathered}

\to \sf \red{-ln|sin2x|+c}

\to \sf - \ln |2sinx.cosx|+c

\to \sf - \ln |sinx.cosx|+(\ln 2+c)

\leadsto - \sf \red{\ln |sinx.cosx|+c}\ \; \bigstar

★ Alternate Method :

\displaystyle \sf \int \dfrac{sin^2x-cos^2x}{sinx.cosx}

\displaystyle \to \sf \int \left( \dfrac{sin^2x}{sinx.cosx}-\dfrac{cos^2x}{sinx.cosx}\right)dx

\begin{gathered}\displaystyle \to \sf \int \left( \dfrac{sinx}{cosx} -\dfrac{cosx}{sinx} \right)dx\\\\\to\ \sf \int (tanx-cotx)dx\\\\\to \sf \int tanx.dx-\int cotx.dx\\\\\to \sf ln|secx|-ln|sinx|+c\end{gathered}

\to \sf ln\left| \dfrac{secx}{sinx}\right|+c

\begin{gathered}\to \sf ln\left| \dfrac{1}{sinx.cosx} \right|+c\\\\\end{gathered}]

\leadsto \sf \pink{-ln|sinx.cosx|+c}\ \; \bigstar

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</span>
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