The square root of 52
the third answer
Given =
Two similar pyramid have base area of 12.2 cm² and 16 cm².
surface area of the larger pyramid = 56 cm²
find out the surface area of the smaller pyramid
To proof =
Let us assume that the surface area of the smaller pyramid be x.
as surface area of the larger pyramid is 56 cm²
Two similar pyramid have base area of 12.2 cm² and 16 cm².
by using ratio and proportion
we have
ratio of the base area of the pyramids : ratio of the surface area of the pyramids

x = 12.2 ×56×
by solvingthe above terms
we get
x =42.7cm²
Hence the surface area of the smaller pyramid be 42.7cm²
Hence proved
The first five terms of the sequence are 1, 4, 7, 10, 13.
Solution:
Given data:


General term of the arithmetic sequence.
, where d is the common difference.
d = 3

Put n = 2 in
, we get



Put n = 3 in
, we get



Put n = 4 in
, we get



Put n = 5 in
, we get



The first five terms of the sequence are 1, 4, 7, 10, 13.
Answer:
n<50
Step-by-step explanation:
7/2*5n + 14<49
7n/2*5+14<49
(7n)+(2*5)14/2*5 <49
7n+10*14/2*5 <49
7n+140/2*5 <49
7n+140/10 <49
7n+140 < 10*49
7n+140 < 490
(7n+140)+(-140)<490+(-140)
7n+140-140<490-140
7n<350
7n/7 < 350/7
n<2*5^2*7/7
n<2*5^2
n<2*25
n<50
Answer:
ugh should i drop out
Step-by-step explanation: