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scoundrel [369]
3 years ago
10

Shanice spent half of her weekly allowance on cloths. To earn more money her parents let her clean the gutters for $7. What is h

er weekly allowance if she ended with $14?
Mathematics
1 answer:
Anastaziya [24]3 years ago
8 0

Answer:

$14

Step-by-step explanation:

After Shanice spent half of her allowance and earned $7, she is left with $14.

This means the remaining of her weekly allowance is $7, This can be derived by subtracting $7 from 15 - $14 - $7 = $7

This means that it is $7 that remains after spending half of her weekly allowance

her weekly allowance = $7 x 2 = $14

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Multiplier method increase £88 by 14%
Morgarella [4.7K]

Answer:

if you just want 14% of 88

14% of 88 = 12.32, 0.14 * 88

if you want 14% of 88 + 88

114% of 88 = 100.32, 1.14 * 88

Step-by-step explanation:

2% of x = 0.02 * x

20% of x = 0.2 * x

200% of x = 2 * x

6 0
3 years ago
3 sides of the triangle are distinct prime numbers. What is the smallest possible perimeter of the triangle?
Nitella [24]

Answer:

the smallest possible perimeter is 6

Step-by-step explanation:

since the smallest possible prime number is 2 it would make since if each side is 2 which makes the smallest perimeter possible. i really hope this helped :)

5 0
3 years ago
Read 2 more answers
Below is the normal distribution curve for height (inches) of NBA basketball players.
VladimirAG [237]

Answer:  standard deviation = 8

This is because mu = 75 is the mean, which is at the very exact center of this distribution. One space to the right is 83, which is 83-75 = 8 units away from the center. This distance is exactly one standard deviation. We can say "83 is one standard deviation larger than 75".

Or you could note the distance from 67 to 75 is also 8, because 75-67 = 8. Each tickmark represents stepping one standard deviation in distance.

5 0
3 years ago
How do you solve these equations? I don't want you to answer all of them, just tell me how to solve each type of equation on the
miss Akunina [59]

Answer:

8. Identify the common denominator; express each fraction using that denominator; combine the numerators of those rewritten fractions and express the result over the common denominator. Factor out any common factors from numerator and denominator in your result. (It's exactly the same set of instructions that apply for completely numerical fractions.)

9. As with numerical fractions, multiply the numerator by the inverse of the denominator; cancel common factors from numerator and denominator.

10. The method often recommended is to multiply the equation by a common denominator to eliminate the fractions. Then solve in the usual way. Check all answers. If one of the answers makes your multiplier (common denominator) be zero, it is extraneous. (10a cannot have extraneous solutions; 10b might)

Step-by-step explanation:

For a couple of these, it is helpful to remember that (a-b) = -(b-a).

<h3>8d.</h3>

\dfrac{5}{x+2}+\dfrac{25-x}{x^2-3x-10}=\dfrac{5(x-5)}{(x+2)(x-5)}+\dfrac{25-x}{(x+2)(x-5)}\\\\=\dfrac{5x-25+25-x}{(x+2)(x-5)}=\dfrac{4x}{x^2-3x-10}

___

<h3>9b.</h3>

\displaystyle\frac{\left(\frac{x}{x-2}\right)}{\left(\frac{2x}{2-x}\right)}=\frac{x}{x-2}\cdot\frac{-(x-2)}{2x}=\frac{-x(x-2)}{2x(x-2)}=-\frac{1}{2}

___

<h3>10b.</h3>

\dfrac{3}{x-1}+\dfrac{6}{x^2-3x+2}=2\\\\\dfrac{3(x-2)}{(x-1)(x-2)}+\dfrac{6}{(x-1)(x-2)}=\dfrac{2(x-1)(x-2)}{(x-1)(x-2)}\\\\3x-6+6=2(x^2-3x+2) \qquad\text{multiply by the denominator}\\\\2x^2-9x+4=0 \qquad\text{subtract 3x}\\\\(2x-1)(x-4)=0 \qquad\text{factor; x=1/2, x=4}

Neither solution makes any denominator be zero, so both are good solutions.

8 0
3 years ago
9. (12 pts) daniel is paying $600 for his auto insurance, and he is wondering if he is overpaying compared to his friends. he se
Karolina [17]

Answer:

Step-by-step explanation:

1) The sample and the population of this study is the friends who replied his email which includes in his contact list. then, the number of the replied to his email are 9 friends.

population: the whole friends include in his contact list.

3) Type I error occurs when one incorrectly rejects the null hypothesis

Here there is possibility of type I error

7 0
4 years ago
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