The solution for the problem is:Area of the box is computed by A = 2wl + 2lh + 2hw,where w - width,the l - length, and the h - height.but we need to change that, so the formula would be:A = 2 a² + 4 a h = 300 cm²h = a (the box is a cube) A = 6 a² = 300 cm²a² = 50a = 5 cmV = a³ = 5³ = 125cm³
2Al + 3Pb(NO3)2 ➡️ Al(NO3)3 + 3Pb
Al: 2 Al: 2
Pb: 3 Pb: 3
N: 2 N: 3
O: 6 O: 9
6Al + 9Pb(NO3)2 ➡️ 6Al(NO3)3 + 9Pb
Al: 6 Al: 6
Pb: 9 Pb: 9
N: 18 N: 18
O: 54 O: 54