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mr_godi [17]
3 years ago
12

What's the horizontal asymptote of f(x)=x-3/x+2

Mathematics
1 answer:
jasenka [17]3 years ago
4 0

Answer:

y=1

Step-by-step explanation:

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During the school fundraiser, lsaac sold tubs of cookies dough for $15 each. He made $165. Write an equation that could be used
gregori [183]

165\15= number of tubs

165 divided by 15 equals the amount of the tubs that he sold.

(I assume the two different name things, isaac&dominic, is a mistake since there isnt any information for Dominic)

3 0
3 years ago
The sum of reciprocals of rehman’s ages 3 years ago and 5 years from now is 1/3. Find his present age
Afina-wow [57]

Answer:

His age is 7 years.

Step-by-step explanation:

Let Rehman's  present age be x years.

1 / (x - 3) + 1 /(x + 5) = 1/3

Multiply through by the LCD 3(x - 3)(x + 5):

3(x + 5) + 3(x - 3) = (x + 5)(x - 3)

3x + 15 + 3x - 9 = x^2 + 2x - 15

x^2 + 2x - 6x - 30 + 9 = 0

x^2 - 4x - 21 = 0

(x - 7)(x + 3) = 0

x = 7  (answer).

6 0
3 years ago
Statistics Question Q9
Tanzania [10]

Answer:

D. is the correct one.........

6 0
2 years ago
Read 2 more answers
Find the perimeter of the figure to the nearest hundredth.
bekas [8.4K]

Answer:

38.56

Step-by-step explanation:

8 0
3 years ago
Find the average value of f over region
SVETLANKA909090 [29]
D is a right triangle with base length 1 and height 8, so the area of D is \dfrac12(1)(8)=4.

The average value of f(x,y) over D is given by the ratio

\dfrac{\displaystyle\iint_Df(x,y)\,\mathrm dA}{\displaystyle\iint_D\mathrm dA}

The denominator is just the area of D, which we already know. The average value is then simplified to

\displaystyle\frac74\iint_Dxy\,\mathrm dA

In the x,y-plane, we can describe the region D as all points (x,y) that lie between the lines y=0 and y=8x (the lines which coincide with the triangle's base and hypotenuse, respectively), taking 0\le x\le1. So, the integral is given by, and evaluates to,

\displaystyle\frac74\int_{x=0}^{x=1}\int_{y=0}^{y=8x}xy\,\mathrm dy\,\mathrm dx=\frac78\int_{x=0}^{x=1}xy^2\bigg|_{y=0}^{y=8x}\,\mathrm dx
=\displaystyle56\int_{x=0}^{x=1}x^3\,\mathrm dx
=14x^4\bigg|_{x=0}^{x=1}
=14
3 0
3 years ago
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