Question

Polygon ABCD is translated to create polygon A'B'C'D'. Point A is located at (1,5) os located at (-2,1). What is the distance from B to B'?
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Answer 1

Answer:

The distance from B to B' is 5 units

Step-by-step explanation:

The complete question is

Polygon ABCD is translated to create polygon A'B'C'D'. Point A is located at (1,5) and point A' is located at (-2,1). What is the distance from B to B'?

we know that

In a translation the figure maintains its dimensions and internal angles

so

AA'=BB'=CC'=DD'

The distance BB' is the same that the distance AA'

Find the distance AA'

the formula to calculate the distance between two points is equal to

$d=\sqrt{(y2-y1)^{2}+(x2-x1)^{2}}$

we have

A(1,5),A'(-2,1)

substitute in the formula

$AA'=\sqrt{(1-5)^{2}+(-2-1)^{2}}$

$AA'=\sqrt{(-4)^{2}+(-3)^{2}}$

$AA'=\sqrt{25}$

$AA'=5\ units$

therefore

The distance from B to B' is 5 units