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dusya [7]
3 years ago
15

A woman is standing at the edge of a slow-moving river which is one mile wide, and she wishes to return to her campground on the

opposite side of the river. Assume that the woman can walk at 5 miles per hour and swim at 3 miles per hour, and that she will first swim to cross the river and then walk the remaining distance to the campground, which is 10 miles downstream from the point directly across the river from the woman's starting point. What route will take the least amount of time?
Mathematics
1 answer:
vesna_86 [32]3 years ago
7 0

Answer:

the best option would be to swim

Step-by-step explanation:

Hello! To solve this problem we must follow the following steps.

1. remember the concept of uniform motion with constant speed, which establishes the following equation

t=\frac{X}{V}

where

t=time

x=distance

V=speed

2. Calculate the time it takes to swim and calculate the time it takes to walk

walking:

x=10mile

v=5milles/h

t=\frac{10}{5} =2h

swimming

x=1mile

v=3milles/h

t=\frac{1}{3} =0.3h

3. Compare both results and choose the one with the least time.

as you can see it takes less time swimming, so this would be the best way

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Answer:

12 1/9 is your answer.

Step-by-step explanation:

Since 7+5 is 12 you got your first part. Now you have to find a thing that matches which is 1/9

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PLEASE HELP! THiS IS DUE!!!!!!!! I Will MAKE BRAINlST
9966 [12]

Answer:

\mathrm{26.\qua\:H\quad\:2 \dfrac{ 1  }{ 4  }\qua\:mi}

\mathrm{27.\qua\:D\quad\: 9\dfrac{ 1  }{ 8  }\qua\:lb}

\mathrm{28.\qua\:H\quad\:14.6}

\mathrm{29.\qua\:C\quad\:25\%}

\mathrm{30.\qua\:J\quad\:33.912\qua\ ft^{3} }

Step-by-step explanation:

26.

\mathrm{\dfrac{ 3  }{ 4  }\:mile\:per\:one\:hour}

\mathrm{To\:find\:how\:far\:Jet's\:cousin\:can\:walk\:in\:3\:hours\:,\:we\:multiply\:\dfrac{ 3  }{ 4  }\:by\:3}

3 \times   \dfrac{ 3  }{ 4  }

\mathrm{Express\: 3 \times   \left(  \dfrac{ 3  }{ 4  }    \right)\:as\:a\:singe\:fraction}

\dfrac{ 3 \times  3  }{ 4  }

\mathrm{Multiply\:3\:and\:3\:to\:get\:9}

\dfrac{ 9  }{ 4  }

\mathrm{Convert\:\dfrac{ 9  }{ 4  }\:to\:a\:mixed\:number}

2 \dfrac{ 1  }{ 4  }

\mathrm{So\:she\:can\:walk\:2 \dfrac{ 1  }{ 4  }\:miles\:in\:3\:hours}

27.

\mathrm{Since\:we\:want\:to\:find\:how\:many\:pounds\:both\:pumpkins\:weigh\:together,\:we\:have\:to\:add.}

5 \dfrac{ 3  }{ 4  }  +3 \dfrac{ 3  }{ 8  }

\mathrm{Turn\:both\:mixed\:fractions\:into\:improper\:fractions}

\dfrac{ 23  }{ 4  }  + \dfrac{ 27  }{ 8  }

\mathrm{Least\:common\:multiple\:of\:4\:and\:8\:is\:8}

\mathrm{Multiples\:of\:4}:\quad4,8,12,16,20

\mathrm{Multiples\:of\:8}:\quad8,16,24,32,40

\dfrac{ 23  }{ 4  }  + \dfrac{ 27  }{ 8  }

\mathrm{Convert\:  \dfrac{ 23  }{ 4  }   \:and\:  \dfrac{ 27  }{ 8  }   \:to\:fractions\:with\:denominator\:8}

\dfrac{ 23 \times  2  }{ 4 \times  2  }  + \dfrac{ 27  }{ 8  }

\mathrm{Simplify}

\dfrac{ 46  }{ 8  }  + \dfrac{ 27  }{ 8  }

\mathrm{Since\:  \dfrac{ 46  }{ 8  }\:and\:\dfrac{ 27  }{ 8  }\:have\:the\:same\:denominators,\:add\:them\:by\:adding\:their\:numerators}

\dfrac{ 46+27  }{ 8  }

\mathrm{Add\:46\:and\:27\:to\:get\:73}

\dfrac{ 73  }{ 8  }

\mathrm{Convert\:\dfrac{ 73  }{ 8  }\:to\:a\:mixed\:number}

9 \dfrac{ 1  }{ 8  }

\mathrm{Both\:pumpkins\:weighed\:9 \dfrac{ 1  }{ 8  }\:pounds\:all\:together}

28.

Since the question is asking us "How many more miles did Alyce travel than Jason", we have to subtract the miles Jason traveled from the miles Alyce traveled.

29.193-14.593

\mathrm{Subtract\:14.593\:from\:29.193\:to\:get\:14.6}

14.6

\mathrm{Alyce\:traveled\:14.6\:more\:miles\:than\:Jason}

29.

For this question, we must find "10 is what percent of 40"

The equation for this is:

\dfrac{ 10  }{ 40  }   \times  100

\mathrm{Simplify\:  \dfrac{ 10  }{ 40  }   \:to\:  \dfrac{ 1  }{ 4  }   }

\dfrac{ 1  }{ 4  }   \times  100

\mathrm{Multiply\:  \dfrac{ 1  }{ 4  }\:and\:100\:to\:get\:  \dfrac{ 100  }{ 4  }   }

\dfrac{ 100  }{ 4  }

\mathrm{Divide\:100\:by\:4\:to\:get\:25}

25

\mathrm{So\:she\:recieved\:a\:25\%\:off\:discount}

To check if this is correct, you can do the following below:

What is 25 percent (%) off $40?

Use the formula and replace the given values:

Amount Saved = Original Price x Discount % / 100. So,

Amount Saved = 40 x 25 / 100

Amount Saved = 1000 / 100

Amount Saved = $10

In other words, a 25% discount for an item with original price of $40 is equal to $10

 

30.

Given that the calculated volume of the drum is 37.68 ft³ and it is 90% full, it implies that the current volume is calculated as:

\mathrm{Current\:compacity} =  90 \%   \times  37.68

\mathrm{Turn\:90\%\:into\:a\:decimal}

\mathrm{Current\:compacity} =  0.9   \times  37.68

\mathrm{Multiply\:0.9\:and\:37.68\:to\:get\:33.912}

33.912

\mathrm{The\:current\:compacity\:of\:the\:drum\:is\:33.912\:ft^{3} }

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