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3 years ago

Is this answer correct?

Mathematics

2 answers:

ludmilkaskok [199]3 years ago

6 0

Answer:

yes i belive so

Step-by-step explanation:

lakkis [162]3 years ago

5 0

Answer:

yes

Step-by-step explanation:

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I need help being guided through this question. I thought it was SAS. But not sure.

topjm [15]

Answer:

ASA

Step-by-step explanation:

You know the angle of 90 degrees on both sides. Then you see they have the same side, and then you see they have the same angle (vertical angles)

3 0

3 years ago

Simplify the expression: (-4 x^4 y^5)(5 x^7 y^3)

AleksandrR [38]

$(-4x^4y^5)(5x^7y^3)=(-4)(5)(x^4x^7)(y^5y^3)\\\\=-20x^{4+7}y^{5+3}=-20x^{11}y^8$

8 0

4 years ago

30 POINTS!!!!!!!!

saul85 [17]

Answer:

1. a square bulletin board has an area of 100ft^2 what is the side length of the bulletin board?

Answer: 10 ft

• Area = side × side

$100 = {s}^{2} \\ s = \sqrt{100} \\ side = 10 \: ft$

2.which is the correct classification of the vaule 2pi?

D. real,irrational

→ It is irrational because it has no denominator, it is real because it has no imaginary part, and it can be plotted on a number line.

3. simplify each expression

$\hookrightarrow \: - 9x + 12 - 10 + x \\ = ( - 9x + x) + 12 - 10 \\ = { \boxed{ - 8x + 2}} \\ \\ \\ \hookrightarrow \: \frac{3}{4} x + 17 - \frac{1}{4} x - 19 \\ \\ = \frac{3}{4} x - \frac{1}{4} x + 17 - 19 \\ \\ { \boxed{ = \frac{1}{2} x - 2}} \\ \\ \\ \hookrightarrow \: 13 + 12x - 4x - 14 \\ = 13 + 8x - 14 \\ { \boxed{ = 8x - 1}} \\ \\ \\ \hookrightarrow \: - \frac{3}{2} x - 68 + 2x + 8 \\ \\ = - \frac{3}{2} x + 2x - 68 + 8 \\ \\ { \boxed{ = \frac{1}{2}x - 60 }}$

3 0

3 years ago

Please help with number 1 please ?

Oxana [17]

It's asking you to set -x and x equal to each other...

-x = x
2x = 0
x = 0.

8 0

3 years ago

The length of a rectangle is twice its width. If the perimeter of the rectangle is 54cm , find its length and width.

wariber [46]

Lets with be - x
then length - 2x
Perimeter= 2*x+2*2x=2x+4x=6x
P=54
6x=55,
x=9 width
2x=2*9=18 length

3 0

3 years ago