Answer:
The 80% confidence interval for the mean number of toys purchased each year is between 7.5 and 7.7 toys.
Step-by-step explanation:
We have that to find our
level, that is the subtraction of 1 by the confidence interval divided by 2. So:

Now, we have to find z in the Ztable as such z has a pvalue of
.
That is z with a pvalue of
, so Z = 1.28.
Now, find the margin of error M as such

In which
is the standard deviation of the population and n is the size of the sample.

The lower end of the interval is the sample mean subtracted by M. So it is 7.6 - 0.1 = 7.5
The upper end of the interval is the sample mean added to M. So it is 7.6 + 0.1 = 7.7
The 80% confidence interval for the mean number of toys purchased each year is between 7.5 and 7.7 toys.
Answer:
2,650 pounds
Step-by-step explanation:
Given data
Amount paid= $848
Rate = 32 cents= $0.32
Hence the amount she purchased is
Quantity= Amount* Rate
Quantity = 848/0.32
Quantity= 2650
D=dimes
Q=quarters
D=32+Q
Q=?
D+Q=$11.6
D=(32*10)+Q=
$3.2+Q
$11.6-$3.2=$8.4
Each quarter must include 1 dime from now on because there’s 32 MORE dimes than quarters. $8.4/$0.35=24. (Divide 8.4 dollars by 1quarter+1dime, which is 35 cents.)
35 cents goes into $8.4 dollars 24 times. This means there’s 24 quarters and 24 more dimes. Returning to our original equations,
D=32+24
D=56
Q=24
This follows the rule of having 32 more dimes than quarters and the two add up to the correct amount, $11.60
There’s 56 dimes and 24 quarters