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Yuki888 [10]
3 years ago
5

How do I Solve this problem?

Mathematics
2 answers:
nlexa [21]3 years ago
6 0
U would factor by grouping and get x^2(x-2) + 3(x-2) and then get (x^2 +3) (x-2)
katrin [286]3 years ago
5 0
Firstly, =\left(x^3-2x^2\right)+\left(3x-6\right)

\mathrm{Factor\:out\:}x^2\mathrm{\:from\:}x^3-2x^2\mathrm{:\quad }x^2\left(x-2\right)
\mathrm{Factor\:out\:}3\mathrm{\:from\:}3x-6\mathrm{:\quad }3\left(x-2\right)
=x^2\left(x-2\right)+3\left(x-2\right)
\mathrm{Factor\:out\:common\:term\:}\left(x-2\right)
=\left(x-2\right)\left(x^2+3\right)

Hope this helps.


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Answer:

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Step-by-step explanation:

We have that to find our \alpha level, that is the subtraction of 1 by the confidence interval divided by 2. So:

\alpha = \frac{1 - 0.8}{2} = 0.1

Now, we have to find z in the Ztable as such z has a pvalue of 1 - \alpha.

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M = 1.28\frac{1.5}{\sqrt{305}} = 0.1

The lower end of the interval is the sample mean subtracted by M. So it is 7.6 - 0.1 = 7.5

The upper end of the interval is the sample mean added to M. So it is 7.6 + 0.1 = 7.7

The 80% confidence interval for the mean number of toys purchased each year is between 7.5 and 7.7 toys.

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Charmaine pays $848 for landscaping rocks for a project. The cost per pound is 32 cents. How many pounds did she purchase? 0.265
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Q=quarters

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35 cents goes into $8.4 dollars 24 times. This means there’s 24 quarters and 24 more dimes. Returning to our original equations,
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This follows the rule of having 32 more dimes than quarters and the two add up to the correct amount, $11.60

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