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MatroZZZ [7]
3 years ago
14

I have this question in Geometry that I need help with, can you help me solve it?

Mathematics
1 answer:
Degger [83]3 years ago
6 0

Answer(6,1)

Step-by-step explanation:

you need to use the midpoint formula

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A bridge on a river is modeled by the equation h = -0.2d2 + 2.25d, where h is the height and d is the horizontal distance. For c
icang [17]
The answer is 2.2108
Solution:
first equation:
h = -0.2d² + 2.25d-d + 6h = 21.77
2nd equation:-d + 6h = 21.77d = 6h - 21.77
Then substitute:h = -0.2(6h - 21.77)² + 2.25(6h - 21.77)h = 3.9968
Answer:d = 2.2108

6 0
3 years ago
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Please help and thank you
ICE Princess25 [194]

Answer:

30

Step-by-step explanation:

15/3=5

5 x 5 = 25

25 + 5 = 30

4 0
2 years ago
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Please helppp!!!!!!!!!
koban [17]

It is (1,15). I recommend using a website called desmos because it helps with graphing.

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3 years ago
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PLS HELP Find the m∠RLU.<br> A. 10º<br> B. 6º<br> C. 25º<br> D. 50º
alexdok [17]

Rlu is 50 as rlu and alu are equal

7 0
3 years ago
The length of a rectangle is 5 ft less than three times the width, and the area of the rectangle is 50 ft². Find the dimensions
Mariulka [41]

Answer

Length = 10 ft

Width = 5 ft

Explanation

Area of the rectangle given = 50 ft²

Let the width of the rectangle be x

So this means the length of the rectangle will be 3x - 5

What to find:

The dimensions of the rectangle.

Step-by-step solution:

Area of a rectangle = length x width

i.e A = L x W

Put A = 50, L = 3x - 5, W = x into the formula.

\begin{gathered} 50=(3x-5)x \\ 50=3x^2-5x \\ 3x^2-5x-50=0 \end{gathered}

The quadratic equation can now be solve using factorization method:

\begin{gathered} 3x^2-5x-50=0 \\ 3x^2-15x+10x-50=0 \\ 3x(x-5)+10(x-5)=0 \\ (3x+10)(x-5)=0 \\ 3x+10=0\text{ }or\text{ }x-5=0 \\ 3x=-10\text{ }or\text{ }x=5 \\ x=-\frac{10}{3}\text{ }or\text{ }x=5 \end{gathered}

Since the dimension can not be negative, hence the value of x will be = 5.

Therefore, the dimensions of the rectangle will be:

\begin{gathered} Length=3x-5=3(5)-5=15-5=10\text{ }ft \\  \\ Width=x=5\text{ }ft \end{gathered}

7 0
10 months ago
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