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german
3 years ago
8

(1,2)m=7 who has this answer

Mathematics
1 answer:
Paraphin [41]3 years ago
5 0

y-y1 = m(x-x1)

y-2 = 7(x-1)  point slope form

y-2 = 7x-7

add 2

y=7x-5 slope intercept form

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Which concept can be used to prove that the diagonals of a parallelogram bisect each other? congruent triangles similar triangle
ch4aika [34]

<u>Answer </u>

The concept can be used to prove that the diagonals of a parallelogram bisect each other is congruent triangles

<u>Explanation </u>

In a parallelogram, opposite sides are equal and parallel.

The two diagonals in the parallelogram make four triangles. opposite triangles are congruent. That means two pair of congruent triangle are here.

Using congruence of triangles, we can prove the diagonals of a parallelogram bisect each other

4 0
3 years ago
Read 2 more answers
3(2x + 12) = -2(x - 4) + x
mart [117]

Answer:

-4

Step-by-step explanation:

1. Use the distributive property to get 6x + 36 = -2x + 8 + x

2. Combine like terms 6x + 36 = -x + 8

3. Subtract 36 on both sides. 7x + 36 = 8 > 7x = -28

4. Divide by 7

-28/7 = -4  x=4

5 0
4 years ago
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Together, Sarah's two cats have the same mass as her dog, 11 kg. The mass of one cat is
levacccp [35]
First, lets do all calculations in kg. 1kg=1000 grams
Lets set 1 cat's mass as x.
Lets set the other cat's mass as y.
1) x+y=11
2) y=x+1.5   

Lets plug eq 2 into eq 1.
x+x+1.5=11
2x+1.5=11
2x=9.5
x=4.75 kg

If one cat weighs 4.75 kg, then the other must weigh 6.25 kg.




6 0
3 years ago
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Estimate the amount of time the trip will take. 290 miles at 40 mph 5 and 1/4 hours 7 hours 6 and 1/2 hours 7 and 1/4 hours
yan [13]
290÷40= 7.25

the answer is 7 1/4
8 0
4 years ago
A. Show
nydimaria [60]

a. Recall the double angle identities:

\sin^2x=\dfrac{1-\cos2x}2

\cos^2x=\dfrac{1+\cos2x}2

Then

\sin^2x\cos^2x=\dfrac{(1-\cos2x)(1+\cos2x)}4=\dfrac{1-\cos^22x}4

Applying the identity again, we have

\sin^2x\cos^2x=\dfrac{1-\frac{1+\cos4x}2}4=\dfrac{2-(1+\cos4x)}8=\dfrac{1-\cos4x}8

as required.

b. Using the result from part (a),

\sin^2x\cos^2x=\dfrac{1-\cos4x}8=\dfrac{2-\sqrt2}{16}

\implies\cos4x=\dfrac1{\sqrt2}

\implies4x=\dfrac\pi4+2n\pi\text{ or }4x=-\dfrac\pi4+2n\pi

(where n is any integer)

\implies\boxed{x=\pm\dfrac\pi{16}+\dfrac{n\pi}2}

8 0
3 years ago
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