What is the perimeter of a rectangle if the length is (3x + 2) and the width is (2x - 5)
1 answer:
Answer: 10x-6
Step-by-step explanation:
we know that perimeter P is 2L+2W
2L= 2(3x+2)=6x+4
2W=2(2x-5)=4x-10
P=6x+4+4x-10=10x-6
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Hope this helps!
Answer:
ok 2hats the qeustion?
360=x+x+(2x+3)+(2x+3)
we have 360=2x+2x+2x+6
360-6=6x
354=6x
x=354/6=59
x=59
The ratio is 21.1 now give me my 33 dolar
Since 4 circles are circumscribed by a square, then the side length of the square is 8
So the area of the square is 8^2 = 64
The area of 4 squares is 4 * pi*2^2 = 16pi
So the answer will be 64 - 16pi