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3 years ago

12

Brian irons 2/9 of his shirt in 3 3/5 minutes. Brian irons at a constant rate. At this rate, how much of his shirt does he iron

each minute?

1 answer:

Naily [24]3 years ago

3 0

You have to divide both sides by 3 3/5
Or multiply by 5/18, the inverse of 3 3/5.

It should get you 5/81 of his shirt per minute

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The Interest Rate, The Time And The Principle Amount

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Find the circumference of a circle that has a 25-inch radius. Use 3.14 to approximate π.

Sergio [31]

$\huge \tt \color{pink}{A}\color{blue}{n}\color{red}{s}\color{green}{w}\color{grey}{e}\color{purple}{r }$

$\large\underline{ \boxed{ \sf{✰\:Important\: point's }}}$

➣ Circle:- A two-dimensional geometric figure, a line, consisting of the set of all those points in a plane that are equally distant from a given point (center).
➣ Circumference:- The line that bounds a circle or other two-dimensional figure

${ \rule{70mm}{2.9pt}}$

★ also circumference of a circle is also known as it's perimeter

➣To find circumference of circle when use formula

${ \boxed{✜\underline{ \boxed{ \sf{\: Circumference \: of \: circle= \: 2\pi \: r}}}✜}}$

➢ r = radius (25inch.)
➢ value of π is 3.14

${ \rule{70mm}{2.9pt}}$

$\large\underline{ \boxed{ \sf{✰\: Let's\:solve }}}$

$\sf{➛ \: Circumference \: of \: circle = 2 \times 3.14 \times 25} \\ \sf{➛ \: Circumference \: of \: circle =2 \times 78.5} \\ \sf{➛ \: Circumference \: of \: circle =157inch}$

★ Hence circumference of circle=157inch

$\large\underline{ \boxed{ \sf{➪\:157inch. }}}$

${ \rule{70mm}{2.9pt}}$

Hope it helps !

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2 years ago

Please help question in the picture

zubka84 [21]

Its 56 I DID this you could only multiple the straight sides

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3 years ago

Jack looks at a clock tower from a distance and determines that the angle of elevation of the top of the tower is 40°. John, who

zmey [24]

Answer:

18.7939 m

Step-by-step explanation:

-Let x be the distance between John and clock tower.

-Let y be the vertical distance from the eyes of the two men standing to the top of the clock tower.

#Taking the right triangle ACD:

$\Tan \ theta=\frac{Perpendicular \ Height}{Base}\\\\Tan \ 60\textdegree=\frac{y+1.5}{x}\\\\y=x \ Tan \ 60\textdegree -1.5$

#Taking the right triangle ABD:

$\Tan \ theta=\frac{Perpendicular \ Height}{Base}\\\\Tan \ 40\textdegree=\frac{y+1.5}{x+20}\\\\y=(x+20)\ Tan \ 40\textdegree -1.5$

#We equate the two yo solve for x and y;

$(x+20)\ Tan \ 40\textdegree -1.5=x\ Tan \ 60\textdegree -1.5\\\\(x+20)\ Tan \ 40\textdegree=x\ Tan \ 60\textdegree\\\\0.8391x+16.7820=1.7321x\\\\x=18.7939$

Hence, John's distance from the tower's base is 18.7939 m

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3 years ago