Answer:
-4
Step-by-step explanation:
- y = 3(x+5)²-4
- y= 3(x²+10x+25)-4
- y= 3x²+30x+75-4
- y= 3x²+30x+71
Derivate the function
solve the equation y'= 0
- y'= 6x+30
- 6x+30= 0
- 6x= -30
- x = -5
The extrme value of y is reached in -5
y = 3(-5+5)²-4= -4
Answer:
Part 1) m∠EOD=20°
Part 2) m∠AOD=80°
Step-by-step explanation:
Part 1) Find the measure of angle EOD
we know that °
m∠EOD=m∠EOX-m∠DOX
we have
Observing the figure
m∠EOX=140°
m∠DOX=120°
substitute
m∠EOD=140°-120°=20°
Part 2) Find the measure of angle AOD
we know that °
m∠AOD=m∠DOX-m∠AOX
we have
Observing the figure
m∠AOX=40°
m∠DOX=120°
substitute
m∠AOD=120°-40°=80°
1.25x=1.25 so divided both sides by 1.25 sooo x=1
<h3>
Answer:</h3>
6 hours
<h3>
Step-by-step explanation:</h3>
The two hoses together take 1/3 the time (4/12 = 1/3), so the two hoses together are equivalent to 3 of the first hose.
That is, the second hose is equivalent to 2 of the first hose. Two of the first hose could fill the vat in half the time one of them can, so 6 hours.
The second hose alone can fill the vat in 6 hours.
_____
The first hose's rate of doing work is ...
... (1 vat)/(12 hours) = (1/12) vat/hour
If h is the second hose's rate of doing work, then working together their rate is ...
... (1/12 vat/hour) + h = (1/4 vat/hour)
... h = (1/4 - 1/12) vat/hour = (3/12 -1/12) vat/hour = 2/12 vat/hour
... h = 1/6 vat/hour
so will take 6 hours to fill 1 vat.
