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Volgvan
3 years ago
9

What is the answer to 6(c+5)

Mathematics
1 answer:
Anna [14]3 years ago
3 0

Answer:

6c+30

Step-by-step explanation:

Distribute it!

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A polling company conducted a survey asking 40 fourth year students from Ohio and 33 fourth-year students from Pennsylvania abou
miv72 [106K]

Answer:

The 99.9% confidence interval for the difference between these results is between 12.09 and 25.91 hours per week.

Step-by-step explanation:

Before building the confidence interval, we need to understand the central limit theorem and subtraction between normal variables.

Central Limit Theorem

The Central Limit Theorem estabilishes that, for a normally distributed random variable X, with mean \mu and standard deviation \sigma, the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean \mu and standard deviation s = \frac{\sigma}{\sqrt{n}}.

For a skewed variable, the Central Limit Theorem can also be applied, as long as n is at least 30.

For a proportion p in a sample of size n, the sampling distribution of the sample proportion will be approximately normal with mean \mu = p and standard deviation s = \sqrt{\frac{p(1-p)}{n}}

Subtraction of normal variables:

When two normal variables are subtracted, the mean is the subtraction of the means, while the standard deviation is the square root of the sum of variances.

Ohio had an average of 52, standard deviation of 7.22, sample of 40.

This means that \mu_O = 52, s_O = \frac{7.22}{\sqrt{40}} = 1.1416

Pennsylvania had an average of 33, standard deviation of 10.11, sample of 33.

This means that \mu_P = 33, s_P = \frac{10.11}{\sqrt{33}} = 1.76

Distribution of the difference:

\mu = \mu_O - \mu_P = 52 - 33 = 19

s = \sqrt{s_O^2 + s_P^2} = \sqrt{1.1416^2 + 1.76^2} = 2.1

Confidence interval:

We have that to find our \alpha level, that is the subtraction of 1 by the confidence interval divided by 2. So:

\alpha = \frac{1 - 0.999}{2} = 0.0005

Now, we have to find z in the Ztable as such z has a pvalue of 1 - \alpha.

That is z with a pvalue of 1 - 0.0005 = 0.9995, so Z = 3.29.

Now, find the margin of error M as such

M = zs

M = 3.29*2.1 = 6.91

The lower end of the interval is the sample mean subtracted by M. So it is 19 - 6.91 = 12.09 hours per week

The upper end of the interval is the sample mean added to M. So it is 19 + 6.91 = 25.91 hours per week.

The 99.9% confidence interval for the difference between these results is between 12.09 and 25.91 hours per week.

8 0
3 years ago
Solve the system of linear equations by elimination. 3x+3=3y and 2x−6y=2
Drupady [299]
3x + 3 = 3y         < -- make this 3x - 3y = -3
2x - 6y = 2

multiply by 2 on the first equation
6x - 6y = -6
2x - 6y = 2           
subtract them

4x = -8
x = -2


substitute x = -2 into any of the equation
2x - 6y = 2
2(-2) - 6y = 2
-4 - 6y = 2
-6y = 6
y = -1

So the answer is 
(-2 , -1)
6 0
4 years ago
Read 2 more answers
Solve for x:<br> -3x +5 = 17
valentina_108 [34]

Answer:

x=-4

Step-by-step explanation:

-3x +5 = 17

-3x+5-5=17-5

    -3x=12

 -3x/3 = 12/-3

       x=-4

8 0
3 years ago
Plzz help me i really need help guys
OverLord2011 [107]

Answer:

Figure 1: 226 ft^{2}

Figure 2: 111 mm^{2}

Step-by-step explanation:

For the first figure, you will split it into two rectangles. You would do 28 x 7 for the first rectangle and get 196. Then, you would do 6 x 5 for the second rectangle and get 30. You would then add these two numbers and get the area of 226 ft^{2}}.

For the second figure, you split it into one triangle and two rectangles. For the triangle, you would do 3 x 6 and then divide that by 1/2, since it is a triangle, and you get 9. For the first rectangle, you would do 10 x 7 and you would get 70. For the final rectangle, you would do 8 x 4 and get 32. You would then add all these numbers up and get the area of 111 mm^{2}.

4 0
3 years ago
During the 2015-16 NBA season, J.J. Redick of the Los Angeles Clippers had a free throw shooting percentage of 0.901 . Assume th
ser-zykov [4K]

Answer: 0.5898

Step-by-step explanation:

Given :  J.J. Redick of the Los Angeles Clippers had a free throw shooting percentage of 0.901 .

We assume that,

The probability that .J. Redick makes any given free throw =0.901  (1)

Free throws are independent.

So it is a binomial distribution .

Using binomial probability formula, the probability of getting success in x trials :

P(X=x)^nC_xp^x(1-p)^{n-x}

, where n= total trials

p= probability of getting in each trial.

Let x be binomial variable that represents the number of a=makes.

n= 14

p= 0.901     (from (1))

The probability that he makes at least 13 of them will be :-

P(x\geq13)=P(x=13)+P(x=14)

=^{14}C_{13}(0.901)^{13}(1-0.901)^1+^{14}C_{14}(0.901)^{14}(1-0.901)^0\\\\=(14)(0.901)^{13}(0.099)+(1)(0.901)^{14}\ \ [\because\ ^nC_n=1\ \&\ ^nC_{n-1}=n ]\\\\\approx0.3574+0.2324=0.5898

∴ The required probability = 0.5898

5 0
3 years ago
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