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Elena L [17]
3 years ago
6

Plzz help me i really need help guys

Mathematics
1 answer:
OverLord2011 [107]3 years ago
4 0

Answer:

Figure 1: 226 ft^{2}

Figure 2: 111 mm^{2}

Step-by-step explanation:

For the first figure, you will split it into two rectangles. You would do 28 x 7 for the first rectangle and get 196. Then, you would do 6 x 5 for the second rectangle and get 30. You would then add these two numbers and get the area of 226 ft^{2}}.

For the second figure, you split it into one triangle and two rectangles. For the triangle, you would do 3 x 6 and then divide that by 1/2, since it is a triangle, and you get 9. For the first rectangle, you would do 10 x 7 and you would get 70. For the final rectangle, you would do 8 x 4 and get 32. You would then add all these numbers up and get the area of 111 mm^{2}.

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Select from the drop-down menu to explain how to find the quotient of 156.38 and 100.
Blizzard [7]

Answer:

2 places to the left

Step-by-step explanation:

156.38/100 = 1.5638

6 0
3 years ago
Split the number 76 into the ratio 6:3:7:3 .
kompoz [17]

Answer:

24:12:28:12

Step-by-step explanation:

76÷19=4

6×4:3×4:7×4:3×4

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3 0
3 years ago
15 crackers weigh 69 grams. how many kilograms is this?
Marrrta [24]

Answer:

0.069\ kg

Step-by-step explanation:

we know that

1 kg=1,000 g

so

using proportion

Find out how many kilograms are 69 grams

Let

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\frac{1}{1,000}\frac{kg}{g} =\frac{x}{69}\frac{kg}{g}\\\\x=\frac{69}{1,000}\\\\x=0.069\ kg

6 0
4 years ago
Which of the following is equivalent to the polynomial below?
Gnoma [55]

Answer:

(x-(4+\sqrt{3}i))(x-(4-\sqrt{3}i))

Step-by-step explanation:

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x^2-8x+19

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Note that i^2=-1, then D=12i^2.

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Now, given quadratic expression is equivalent to

(x-(4+\sqrt{3}i))(x-(4-\sqrt{3}i))\\ \\=(x-4-\sqrt{3}i)(x-4+\sqrt{3}i)

6 0
3 years ago
10.5 divided by 1.5 equal show the work out
ratelena [41]
How to solve Problem:

10.5÷1.5

Move both decimals all the way to the right

105÷15

Then solve from there. I'll give you a hint, It's a whole number.

6 0
4 years ago
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