All categories

2 years ago

2+2 is 4, minus one is _

Mathematics

2 answers:

kari74 [83]2 years ago

8 0

Answer:

Step-by-step explanation:

2+2= 4

4-1=3

You answer is 3

Tamiku [17]2 years ago

7 0

Answer: 3

Is this really a question LOL

You might be interested in

The function ()=2,708.92(1.12) − 12 models the amount of money in Caleb's investment account after years.

wolverine [178]

Answer:

d i think

Step-by-step explanation:

5 0

2 years ago

H function is even, odd, or neither. b. g(x) = x² - 2 Is it odd or even

o-na [289]

$g(x) = x^2 - 2 \text{ is even function }$

Solution:

Given that,

$g(x) = x^2 - 2$

We have to find whether the above function is odd or even

If a function is: y = f(x)

If f(-x) = f(x), the function is even

If f(-x) = - f(x), the function is odd

Which is,

$\mathrm{Even\:Function:\:\:A\:function\:is\:even\:if\:}f\left(-x\right)=f\left(x\right)\mathrm{\:for\:all\:}x\in \mathbb{R}\\\\\mathrm{Odd\:Function:\:\:A\:function\:is\:odd\:if\:}f\left(-x\right)=-f\left(x\right)\mathrm{\:for\:all\:}x\in \mathbb{R}$

From given,

$g(x) = x^2 - 2$

Replace x with -x

$g(-x) = (-x)^2 - 2\\\\g(-x) = x^2 - 2$

Therefore,

$g(x) = g(-x)$

Thus the function g(x) is even

4 0

2 years ago

Use the given information to find the exact value of the trigonometric function

eimsori [14]

$\begin{gathered} \csc \theta=-\frac{6}{5} \\ \tan \theta>0 \\ \cos \frac{\theta}{2}=\text{?} \end{gathered}$

Half Angle Formula

$\cos \frac{\theta}{2}=\pm\sqrt[\square]{\frac{1+\cos\theta}{2}}$ $\tan \theta>0\text{ and csc}\theta\text{ is negative in the third quadrant}$ $\begin{gathered} \csc \theta=-\frac{6}{5}=\frac{r}{y} \\ x^2+y^2=r^2 \\ x=\pm\sqrt[\square]{r^2-y^2} \\ x=\pm\sqrt[\square]{6^2-(-5)^2} \\ x=\pm\sqrt[\square]{36-25} \\ x=\pm\sqrt[\square]{11} \\ \text{x is negative since the angle is on the 3rd quadrant} \end{gathered}$ $\begin{gathered} \cos \theta=\frac{x}{r}=\frac{-\sqrt[\square]{11}}{6} \\ \cos \frac{\theta}{2}=\pm\sqrt[\square]{\frac{1+\cos\theta}{2}} \\ \cos \frac{\theta}{2}is\text{ also negative in the 3rd quadrant} \\ \cos \frac{\theta}{2}=-\sqrt[\square]{\frac{1+\frac{-\sqrt[\square]{11}}{6}}{2}} \\ \cos \frac{\theta}{2}=-\sqrt[\square]{\frac{\frac{6-\sqrt[\square]{11}}{6}}{2}} \\ \cos \frac{\theta}{2}=-\sqrt[\square]{\frac{6-\sqrt[\square]{11}}{12}} \\ \\ \end{gathered}$

Answer:

$\cos \frac{\theta}{2}=-\sqrt[\square]{\frac{6-\sqrt[\square]{11}}{12}}$

Checking:

$\begin{gathered} \frac{\theta}{2}=\cos ^{-1}(-\sqrt[\square]{\frac{6-\sqrt[\square]{11}}{12}}) \\ \frac{\theta}{2}=118.22^{\circ} \\ \theta=236.44^{\circ}\text{ (3rd quadrant)} \end{gathered}$

Also,

$\csc \theta=\frac{1}{\sin\theta}=\frac{1}{\sin (236.44)}=-\frac{6}{5}\text{ QED}$

The answer is none of the choices

7 0

6 months ago

30.) Patel bought a model rocket kit from a catalog. The price of the kit was $124.95. The

Nastasia [14]

Answer:

10 to afford it

Step-by-step explanation:

3 0

2 years ago

The Calculate the perimeter of Following Shape: 8cm 5cm

mina [271]

Answer:

where is your shape

Step-by-step explanation:

firstly give shape then we find out perimeter

7 0

2 years ago

Read 2 more answers