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agasfer [191]
3 years ago
8

Need exercise problems with parentheses and variables

Mathematics
1 answer:
topjm [15]3 years ago
7 0

There are many good exercise problems on

https://www.khanacademy.org/

This website also includes exercise problems for just about any subject and/or grade level.

You might be interested in
CAN ANYONE HELP ME PLEASE!!!!!!
HACTEHA [7]
Not sure if this helps

3 0
3 years ago
[02.03]
SVEN [57.7K]

Answer:

2)  Equation 1 and Equation 2 have the same number of solutions.

Step-by-step explanation:

The two given equations are

1)  15x + 6 = 41                and                   2) 2x + 13 = 28

Solving both equations, we get

Solving (1) :   15x + 6 = 41 ⇒   15x  = 41 -  6 = 35

or, x = 35/15 ⇒ x = 7/3

Solving (2) :   2x + 13 = 28⇒   2x  = 28 -  13  = 15

or, x = 15/2 ⇒ x = 15/2

So, from above solutions we can say that Equation 1 and Equation 2 have the same number of UNIQUE solution.

6 0
3 years ago
Please math help and please show work!
Galina-37 [17]
Since they are similar triangles, they are just enlarged versions of each other. This means that the left-most angle of triangle XYZ is also 35°.

Angles in a triangle add up to 180°, so we can find the missing angle by subtracting the two known angles from 180.

180 - 70 - 35 = 75
The right-most angle of triangle XYZ would be 75°.

Hope this helps!
6 0
3 years ago
Can someone help me with this ??
Stolb23 [73]

Answer:

what are your choices

Step-by-step explanation:

6 0
3 years ago
25. Michael is studying population changes in two
g100num [7]

Answer: Average rates of change for Bird A is 0.045 and for Bird B is 3.816.

Step-by-step explanation: Through its graph, a function can be analyzed and be identified its attributes. Average Rate of Change is the ratio of change in the function values to the change of x-value, i.e., it is the slope of the function in a specific interval of x. With the Average it is possible to compare two function.

<u>Average Rate of Change</u>

<em><u>Bird A</u></em>:

For the interval [0,18]:

x₁ = 0 f(0) = 8.3

x₂ = 18 f(18) = 9.1

Average = \frac{f(18) - f(0)}{x_{2} - x_{1} }

Average = \frac{9.1 - 8.3}{18 - 0}

Average = 0.045

<em><u>Bird B</u></em>: y = 3.6(1.06)x

For the interval [0,18]:

x₁ = 0 y = 3.6(1.06)0 = 0

x₂ = 18 y = 3.6(1.06)18 = 68.7

Average = \frac{f(18) - f(0)}{x_{2} - x_{1} }

Average = \frac{68.7 - 0}{18 - 0}

Average = 3.816

The Average Rate for Change for Bird A is 0.045 and for Bird B is 3.816. This means that the population of Bird B increase in rate faster than the population of Bird A.

4 0
3 years ago
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