Perimeter is a continuous line forming the boundary of a closed geometrical figure. perimeter of a pentagon = AB+BC+CD+DE+EA (that is 5 sided figure)
so my plan is easy but effective, calculate all those distances using those coordinates with the aid of distance formular. then you add those distances algebraically .
<u>Answer:</u>
The line equation that passes through the given points is 7x – y = 13
<u>Explanation:</u>
Given:
Two points are A(2, 1) and B(3, 8).
To find:
The line equation that passes through the given two points.
Solution:
We know that, general equation of a line passing through two points (x1, y1), (x2, y2) in point slope form is given by

..........(1)
here, in our problem x1 = 3, y1 = 8, x2 = 2 and y2 = 1.
Now substitute the values in (1)


y – 8 = 7(x – 3)
y – 8 = 7x – 21
7x – y = 21 – 8
7x – y = 13
Hence, the line equation that passes through the given points is 7x – y = 13
Answer:
b not shure tho so yeah bye anwser is B
Answer:
Hence x = y = 2
Step-by-step explanation:
Using the SOH CAH TOA identity
Hypotenuse = 2√2
Opposite = x
theta = 45
Sin theta = opp/hyp
Sin 45 =x/2√2
1/√2 = x/2√2
x = 2√2 * 1/√2
x = 2
To get y we will use the pythagoras theorem;
(2√2)² = x² +y²
(2√2)² = 2²+y²
8 = 4 + y²
y² = 8-4
y² = 4
y = √4
y = 2
Hence x = y = 2
I believe the answer is “one solution”. I hope this helps :)