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3 years ago

10

Write the exponential equation for the given situation. A tennis tournament starts with 128 participants. Each round, half of th

e participants gets eliminated from the tournament

1 answer:

inysia [295]3 years ago

6 0

Answer:

y= 128(1-.5)^t

Step-by-step explanation:

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I’m super confused new topic not sure what to do for this one

geniusboy [140]

There’s no question here.

8 0

2 years ago

What are the zeros of f(x) = x3 + 6x2 + 3x – 10 ?

schepotkina [342]

One of the zeroes would be : x = 1

f (1) = 1^3 + 6(1) ^2 + 3 (1) - 10

f(1) = 1 + 6 + 3 - 10

f (1) = 10 - 10

f (1) = 0

Hope this helps

3 0

3 years ago

9. Alicia Martin's savings account has a principle of $1,200. It earns 6% interest compounded quartly

zavuch27 [327]

Answer:

$9) \$1236.27\,10)\,\$6451.07\, 11)\,\$10,152.87 \,12)\,\$907.95 \,13)\,\$4957.69$

Step-by-step explanation:

9) Since Alicia Martin's savings earns 6% quarterly for two quarters then:

$A=P(1+\frac{r}{n})^{nt}$ ⇒ Amount (A), Principle (P), rate (r) in decimal form, number of compoundings (n) a year and t, in year or its fractions.

$A=P(1+\frac{r}{n})^{nt}\Rightarrow A=1200(1+\frac{0.06}{4})^{4*\frac{1}{2}}\Rightarrow A=\$1236.27$

10) Aubrey Daniel's case:

$A=P(1+\frac{r}{n})^{nt}\Rightarrow A=5725(1+\frac{0.04}{4})^{4*3}\Rightarrow A\approx \$6451.07$

11) As for Angelo, similarly to Alicia.

$A=P(1+\frac{r}{n})^{nt}\Rightarrow A=9855(1+\frac{0.06}{4})^{4*\frac{1}{2}}\Rightarrow A\approx \$10,152.87$

12) Simpson's. For semiannual n=2

$A=P(1+\frac{r}{n})^{nt}\Rightarrow A=860(1+\frac{0.055}{2})^{2*1}\Rightarrow A\approx \$907.95$

13) Jana Lacey amount:

$A=P(1+\frac{r}{n})^{nt}\Rightarrow A=4860(1+\frac{0.04}{4})^{4*\frac{1}{2}}\Rightarrow A\approx \$4957.69$

6 0

3 years ago

Given the parent functions f(x) = log3 (5x − 5) and g(x) = log3 (x − 1), what is f(x) − g(x)?. . a. f(x) − g(x) = log3 (4x − 4).

grandymaker [24]

$f ( x ) = log _{3} ( 5 x - 5 ), g ( x ) =log _{3} ( x - 1 ); \\ f ( x ) - g ( x ) = log _{3}( 5 x - 5 ) - log _{3}( x - 1 ) = \\ log _{3} \frac{5(x-1)}{x-1} = log _{3} 5$
Answer: C ) f ( x ) - g ( x ) = log3 5

8 0

3 years ago

Solve the system and enter the smallest x-coordinate first

ankoles [38]

Answer:
(2,-3)(6,5)
Step-by-step explanation:
We can use substitution to get the equation: x^2-6x+5 = 2x-7
Solve:
x^2-6x+5 = 2x-7
x^2 = 8x-12
x^2-8x+12 = 0 (we now have a polynomial)
(x-6)(x-2) = 0 (set each equation to equal 0 and solve)
x-6 = 0 --> x=6
x-2 = 0 --> x=2
To get the Y coordinates:
y=2(2)-7 --> y = -3
y = 2(6)-7 --> y = 5

Check work:
5 = 6^2-6(6)+5 --> 5 = 36-36 +5 --> 5=5
-3 = 2^2-6(2)+5 --> -3 = 4-12+5 --> -3=-3

4 0

2 years ago