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3241004551 [841]
3 years ago
10

What is the ratio of the number of sides of a quadrilateral to the number of sides of a pentagon?

Mathematics
1 answer:
IgorC [24]3 years ago
3 0
4:5 because a quadrilateral has 4 sides and a pentagon has 5 sides
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Nora invested $1,500 in a bond at a simple interest rate of 3%. How much will the bond be worth in total after 10 years?
attashe74 [19]
<h2>The bond will be worth in total after 10 years is =$1,950</h2>

Step-by-step explanation:

Given,

Nora invested $1,500 in at a bond simple interest rate of 3%

here P= $1500 R= 3% and t = 10year

Simple interest(I) = \frac{P\times R \times t }{100}

                           =$ \frac{1500\times 3 \times 10}{100}

                           =$ 450

<h3>The bond will be worth in total after 10 years is = $1,500+ $450</h3><h3>                                                                                      =$1,950</h3>

8 0
3 years ago
PLLLLEEEEAAASSSEEE HELP ME I REALLY NEED IT IT'S URGENT!!!!!
krok68 [10]
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6 0
3 years ago
During the summer , you want to earn at least $150 per week. You can earn$10 per hour working for a farmer, and $5 per hour baby
almond37 [142]
X = nr. hrs working for a farmer;
y = nr. hrs. babysitting;
x + y <= 25;
10x + 5y >= 150

a) Solve the system => one of the solution is  x =5; y = 20(babysitting)
b) 10 + 12 =22 <= 25; 10*10 + 5*12 = 160 >=150.


7 0
3 years ago
Read 2 more answers
New codes to destroy the First Order are known to exist. With probability 0.6, the codes are hidden by Leia; with probability 0.
elixir [45]

Answer: (a). 0.62 (b). 0.53

Step-by-step explanation:

Let us start by defining some events seen:

Given;

L rep the event that codes hidden Leia

BB represents the codes hidden in BB-8

H is the event that codes hidden by Hah

C-3PO rep the codes hidden in C3PO

Giving the probabilities, we have that

P(L)  =  probability that codes are hidden by Leia = 0.6

P(H) = probability that codes are hidden by Hah = 0.4

where P(BB/L) = 70/10 i.e 70%

P(C-3PO/L) = 1 - P(BB/L) = 1 - 7/10 = 3/10

Also, P(BB/H)  = 1/2 = P(C-3PO/H)

We can say that Han Solo is likely to hide them in aceta BB-8 and C-3PO

To begin,

(a). The question tell us to find the probability that the codes are with BB-8.

First of all, we find P(BB).

P(BB) = P(L)*P(BB/L) + P(H)*P(BB/H)

solving this we get

P(BB) = 0.6*7/10 + 0.4*1/2 = 0.62

Therefore,  the probability that the codes are with BB-8 = 0.62

(b). The second question says;

Given that the codes are with C-3PO, what is the probability the codes were hidden by Han Solo?

This tell us to find P(H/C-3PO)

P(H/C-3PO) = P(C-3PO/H)*P(H) / P(C-3PO/H) + P(C-3PO/L)*P(L)

inputting the values gives us;

P(H/C-3PO) = 1/2 * 0.4 / ( 1/2 *0.4 + 3/10 *0.6) = 0.53

SO we have that the probability the codes were hidden by Han Solo = 0.53

cheers I hope this was helpful!!

3 0
3 years ago
The General Social Survey asked a large number of people how much time they spent watching TV each day. The mean number of hours
DerKrebs [107]

Answer:

Yes, we can conclude that the population standard deviation of TV watching times for teenagers is less than 2.66

Step-by-step explanation:

H0 : σ² = 2.66²

H1 : σ² < 2.66²

X²c = (n - 1)*s² ÷ σ²

sample size, n = 40

Sample standard deviation, s = 1.9

X²c = ((40 - 1) * 1.9²) ÷ 2.66²

X²c = 140.79 ÷ 7.0756

X²c = 19.897

Using a confidence level of 95%

Degree of freedom, df = n - 1 ; df = 40 - 1 = 39

The critical value using the chi distribution table is 25.6954

Comparing the test statistic with the critical value :

19.897 < 25.6954

Test statistic < Critical value ; Reject the Null

Hence, we can conclude that the population standard deviation of TV watching times for teenagers is less than 2.66

8 0
3 years ago
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