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statuscvo [17]
3 years ago
9

Factor completely: A) 64x²-49y² B) 20x²-45y²

Mathematics
2 answers:
BlackZzzverrR [31]3 years ago
8 0

A) This is a difference of two squares. So your equation (a²x² - b²x²) where a and b can be square-rooted ends up being factored to (ax -by)(ax + by).

64x² - 49y² = (8x - 7y)(8x + 7y)

B) Factor out a GCF of 5 from both terms, then you have the same situation as equation A.

20x² - 45y² = 5(4x² - 9y²) = 5(2x - 3y)(2x + 3y)

tigry1 [53]3 years ago
3 0

Use\\a^2-b^2=(a-b)(a+b)\\(ab)^n=a^nb^n\\(\sqrt{a})^2=a\ for\ a\geq0\\------------------------------\\A)\ 64x^2-49y^2=8^2x^2-7^2y^2=(8x)^2-(7y)^2=(8x-7y)(8x+7y)\\\\B)\ 20x^2-45y^2=(\sqrt{20})^2x^2-(\sqrt{45})^2y^2=(*)\\\\\sqrt{20}=\sqrt{4\cdot5}=\sqrt4\cdot\sqrt5=2\sqrt5\\\sqrt{45}=\sqrt{9\cdot5}=\sqrt9\cdot\sqrt5=3\sqrt5\\\\(*)=(2\sqrt5x)^2-(3\sqrt5y)^2=(2\sqrt5x-3\sqrt5y)(3\sqrt5x+3\sqrt5y)

or:\\\\20x^2-45y^2=5\cdot4x^2-5\cdot9y^2=5(4x^2-9y^2)=5[(2x)^2-(3y)^2]\\\\=5(2x-3y)(2x+3y)

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Answer:

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Natasha2012 [34]

Answer:

- 37

Step-by-step explanation:

5 • 2 • ( - 4 ) + 6 ÷ 2

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3 years ago
Graph the equation (please hurry)
IrinaVladis [17]

<em>I</em><em> </em><em>have</em><em> </em><em>attached</em><em> </em><em>the</em><em> </em><em>graph</em><em>!</em><em> </em>

\red{ \rule{35pt}{2pt}} \orange{ \rule{35pt}{2pt}} \color{yellow}{ \rule{35pt} {2pt}} \green{ \rule{35pt} {2pt}} \blue{ \rule{35pt} {2pt}} \purple{ \rule{35pt} {2pt}}

Here are some details about the equation and the graph!

Details of equation ⤵️

  • <u>The</u><u> </u><u>equation</u><u> </u><u>is</u><u> </u><u>written</u><u> </u><u>in</u><u> </u><u>slope-intercept</u><u> </u><u>form</u><u>.</u>
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Details of graph ⤵️

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  • <u>Domain</u><u> </u><u>=</u><u> </u><u>x</u><u>∈</u><u>R</u>
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  • <u>Vertical</u><u> </u><u>intercept</u><u> </u><u>=</u><u> </u><u>(</u><u>0</u><u>,</u><u>1</u><u>)</u>

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Wewaii [24]

Answer:

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Step-by-step explanation:

f(x) = 4^x,

When x = 3,

=> f(3) = 4^3

= 4 * 4 * 4

= 64

7 0
3 years ago
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