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2 years ago

Simplify. 5 • 2 • (–4) + 6 ÷ 2

Mathematics

1 answer:

Natasha2012 [34]2 years ago

4 0

Answer:

- 37

Step-by-step explanation:

5 • 2 • ( - 4 ) + 6 ÷ 2

= 5 • 2 • ( - 4 ) + [ 6 ÷ 2 ]

= 10 • ( - 4 ) + 3

= - 40 + 3

= - 37

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Radha is trying to choose between two bike rental companies, Company A and Company B.

docker41 [41]

Answer:

Part A. After 7 hours the amount charged will be the same

Part B. The cost of renting the bike for that many hours (7) will be 60$.

Step-by-step explanation:

5h + 25 = 6h + 18

5h - 6h = 18 - 25

-h = -7

h = -7/-1

h = 7

Company A.

y = 5h + 25

y = (5*7) + 25

y = 35 + 25

y = 60

Company B.

y = 6h + 18

y = (6*7) + 18

y = 42 + 18

y = 60

6 0

3 years ago

i don't understand how to make it into a graphing form? how do you find the center and radius? (I'm confused because it has a 4x

Vilka [71]

Answer: $\bold{(x-2)^2+(y-3)^2=\dfrac{1}{4}}$

Center = (2, 3) radius = $\bold{\dfrac{1}{2}}$

<u>Step-by-step explanation:</u>

When both the x² and y² values are equal and positive, the shape is a circle. Complete the square to put the equation in format:

(x-h)² + (y-k)² = r² where

(h, k) is the vertex
r is the radius

1) Group the x's and y's together and move the number to the right side

4x² - 16x + 4y² - 24y = -51

2) Factor out the 4 from the x² and y²

4(x² - 4x ) + 4(y² - 6y ) = -51

3) Complete the square (divide the x and y value by 2 and square it)

$4[x^2-4x+\bigg(\dfrac{-4}{2}\bigg)^2]+4[y^2-6y+\bigg(\dfrac{-6}{2}\bigg)^2]=-51+4\bigg(\dfrac{-4}{2}\bigg)^2+4\bigg(\dfrac{-6}{2}\bigg)^2$

= 4(x - 2)² + 4(y - 3)² = -51 + 4(-2)² + 4(-3)²

= 4(x - 2)² + 4(y - 3)² = -51 + 4(4) + 4(9)

= 4(x - 2)² + 4(y - 3)² = -51 + 16 + 36

= 4(x - 2)² + 4(y - 3)² = 1

4) Divide both sides by 4

$(x-2)^2+(y-3)^2=\dfrac{1}{4}$

(h, k) = (2, 3)
$r=\dfrac{1}{2}$

6 0

3 years ago

Lines e and f are parallel. The mAngle9 = 80° and mAngle5 = 55°. Parallel lines e and f are cut by transversal c and d. All angl

brilliants [131]

Answer:

$(A)m\angle 2=125^\circ\\(C)m\angle 8=55^\circ\\(E)m\angle 14=100^\circ$

Step-by-step explanation:

The diagram of the problem is drawn and attached.

Given that:

$m\angle 9 =80^\circ\\m\angle 5 =55^\circ$

$m\angle 5+ m\angle 6=180^\circ\\55^\circ+ m\angle 6=180^\circ\\m\angle 6=180^\circ-55^\circ\\m\angle 6=125^\circ\\$Now:\\m\angle 6 = m\angle 2 $(Corresponging angles)\\Therefore m\angle 2=125^\circ\\$

$m\angle 5= m\angle 8=55^\circ $(Vertically Opposite Angles)$

Also

$m\angle 9+ m\angle 10=180^\circ\\80^\circ+ m\angle 10=180^\circ\\m\angle 10=180^\circ-80^\circ\\m\angle 10=100^\circ\\$Now:\\m\angle 10 = m\angle 14 $(Corresponging angles)\\Therefore m\angle 14=100^\circ\\$