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kow [346]
3 years ago
11

Denise bought 5.2 pounds of rice for 5.29. How much would 2 pounds of rice cost?

Mathematics
1 answer:
viva [34]3 years ago
8 0
2 pounds of rice would cost $1.90
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A jar contains 0.75 liter of blackberry juice and 0.60 liter of blueberry juice. Patrick poured 0.25 liter of guava juice into t
mixas84 [53]

Answer:

1.40 litres; order of operations

Step-by-step explanation:

Part A:

First, write it out in the full form.

#1 (.75 litres of blackberry juice + .60 litres of blueberry juice + .25 litres of guava juice) - .20 litres drank = 1.4 litres of juice remaining in the jar

Part B:

Removing the wordy descriptions from the expression, we get the following:

#2 (.75 + .60 +.25) - .20

or, by adding the numbers in the parentheses first:

#3 (1.60) - .20 = 1.40

#4 1.40 litres of juice left in the jar

The order of operations was used in moving from step #2 to step #3, as operations within the parentheses were conducted before subtracting the .20 litres of juice which were drank.

8 0
3 years ago
Whats 20,000,000x - 3 =
Amiraneli [1.4K]

Answer:

6666666.667 equals x

Step-by-step explanation:

take the 3 to the other side- doin that is became positive

them you divide to find x

4 0
3 years ago
Independent random samples of vehicles traveling past a given point on an interstate highway have been observed on monday versus
quester [9]
Hi! 

To compare this two sets of data, you need to use a t-student test:

You have the following data:

-Monday n1=16; <span>x̄1=59,4 mph; s1=3,7 mph

-Wednesday n2=20;  </span>x̄2=56,3 mph; s2=4,4 mph

You need to calculate the statistical t, and compare it with the value from tables. If the value you obtained is bigger than the tabulated one, there is a statistically significant difference between the two samples.

t= \frac{X1-X2}{ \sqrt{ \frac{(n1-1)* s1^{2}+(n2-1)* s2^{2} }{n1+n2-2}} * \sqrt{ \frac{1}{n1}+ \frac{1}{n2}} } =2,2510

To calculate the degrees of freedom you need to use the following equation:

df= \frac{ (\frac{ s1^{2}}{n1} + \frac{ s2^{2}}{n2})^{2}}{ \frac{(s1^{2}/n1)^{2}}{n1-1}+ \frac{(s2^{2}/n2)^{2}}{n2-1}}=33,89≈34

The tabulated value at 0,05 level (using two-tails, as the distribution is normal) is 2,03. https://www.danielsoper.com/statcalc/calculator.aspx?id=10

So, as the calculated value is higher than the critical tabulated one, we can conclude that the average speed for all vehicles was higher on Monday than on Wednesday.



5 0
4 years ago
Students are playing a game similar to blackjack (with a standard 52 card deck)- trying to get as close to 21 points without goi
son4ous [18]
1/2 wee player a just got 2 so it is out
7 0
3 years ago
Please help. I am doing a test and I do not understand what I am being asked.
Oksanka [162]

Answer:

one

Step-by-step explanation:

i have no idea what kind of test ur taking my guy but have fun

5 0
3 years ago
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