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UkoKoshka [18]
4 years ago
15

A certificate of deposit has an annual simple interest rate of 5.25%. If $567 in interest is earned over a 6 year period, how mu

ch was invested?
Mathematics
1 answer:
Scrat [10]4 years ago
4 0
Find the the amount of interest per year. Since $567 were earned over 6 years, you divide the interest earned by the number of years it took to accumulate it:

$567/6 years = $94.5/year

Divide that by the interest rate which the interest rate needs to be in decimal form:

$94.5/.0525 = $1800
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In March 1999, Bertrand Piccard and Brian Jones attempted to become the first people
lilavasa [31]

Answer:

Distance traveled= 41968.4 km

The domain of the function is t

t(h)= 478

h = hours

Step-by-step explanation:

the distance that they traveled in kilometers, d, can be modeled by

d(t) = 97.8t

where t is the time in hours

They traveled a total of 478 hours.

Distance traveled d(t)

d(t) = 87.8(478)

d(t) = 41968.4

Distance traveled= 41968.4 km

The domain of the function is t

t(h)= 478

3 0
3 years ago
Tiffany starts walking her dog at 1:39 p.M. She gets back home at 2:28 p.M. How long did Tiffany walk her dog?
Tomtit [17]

Answer:

49 minutes

Step-by-step explanation:

Given :

Start time = 1:39 p. M

Return time = 2.28 p. M

Time spent Walking dog = difference between the start time and return time

Return time - start time

(2:28 p.m - 1:39p.m) = 49 minutes

Hence, Tiffany spent 49 minutes walking her dog

4 0
3 years ago
Read 2 more answers
The area of a square ice rink is 405 yards. To the nearest yard, what is the perimeter of the rink?
nasty-shy [4]

Answer:

D. 80 yards

Step-by-step explanation:

i am 99% sure

5 0
3 years ago
How derivative of this absolute value function is like this!
Daniel [21]

Recall the definition of absolute value.

|x| = \begin{cases} x & \text{if } x \ge 0 \\ -x & \text{if } x < 0 \end{cases}

When x,

|x| = x \implies \dfrac{d|x|}{dx} = 1

When x,

|x| = -x \implies \dfrac{d|x|}{dx} = -1

The derivative does not exist at x=0, since the one-sided limits

\displaystyle \lim_{x\to0^-} f'(x) = -1

and

\displaystyle \lim_{x\to0^+} f'(x) = +1

do not match.

So the derivative of |x| is

\dfrac{d|x|}{dx} = \begin{cases} 1 & \text{if } x > 0 \\ -1 & \text{if } x < 0 \\ \text{undefined} & \text{if } x = 0\end{cases}

Now we can write this as

\dfrac{d|x|}{dx} = \dfrac x{|x|} = \dfrac{|x|}x

since

x > 0 \implies |x| = x \implies \dfrac{|x|}x = \dfrac xx = 1

and

x < 0 \implies |x| = -x \implies \dfrac{|x|}x = -\dfrac xx = -1

6 0
2 years ago
What is equivalent to -80=(-7x+5x)+3
hjlf

Answer:

the answer is 41.5

Step-by-step explanation:

-80=-2x+3

-80-3=-2x

-83=-2x

41.5=x

8 0
3 years ago
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