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3 years ago

What is 14 1/4 minus 6 4/5

Mathematics

2 answers:

klemol [59]3 years ago

7 0

Hope this will help u..:)

castortr0y [4]3 years ago

6 0

Answer: 7 9/20

Turn 14 1/4 into an Improper Fraction

Multiply 14*4 and get 56. Now add 1 and get 57.

14 1/4 = 57/4

Turn 6 4/5 into an Improper Fraction

Multiply 6*5 and get 30. Now add 4 and get 34.

6 4/5 = 34/5

Your new problem should be: 57/4 - 34/5

Subtract

57/4 - 34/5 = 149/20

Turn 149/20 into a Mixed Number

149 ÷ 20 = 7.45

7.45 = 7 9/20

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Answer: 2004.3

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3 years ago

Find the vectors T, N, and B at the given point. r(t) = < t^2, 2/3t^3, t >, (1, 2/3 ,1)

maxonik [38]

Answer with Step-by-step explanation:

We are given that

$r(t)=< t^2,\frac{2}{3}t^3,t >$

We have to find T,N and B at the given point t > (1, $2/3$ ,1)

$r'(t)=$

$\mid r'(t) \mid=\sqrt{(2t)^2+(2t^2)^2+1}=\sqrt{(2t^2+1)^2}=2t^2+1$

$T(t)=\frac{r'(t)}{\mid r'(t)\mid}=\frac{}{2t^2+1}$

Now, substitute t=1

$T(1)=\frac{}{2+1}=\frac{1}{3}$

$T'(t)=\frac{-4t}{(2t^2+1)^2} +\frac{1}{2t^2+1}$

$T'(1)=-\frac{4}{9}+\frac{1}{3}$

$T'(1)=\frac{1}{9}=$

$\mid T'(1)\mid=\sqrt{(\frac{-2}{9})^2+(\frac{4}{9})^2+(\frac{-4}{9})^2}=\sqrt{\frac{36}{81}}=\frac{2}{3}$

$N(1)=\frac{T'(1)}{\mid T'(1)\mid}$

$N(1)=\frac{}{\frac{2}{3}}=$

$N(1)=$

$B(1)=T(1)\times N(1)$

$B(1)=\begin{vmatrix}i&j&k\\\frac{2}{3}&\frac{2}{3}&\frac{1}{3}\\\frac{-1}{3}&\frac{2}{3}&\frac{-2}{3}\end{vmatrix}$

$B(1)=i(\frac{-4}{9}-\frac{2}{9})-j(\frac{-4}{9}+\frac{1}{3})+k(\frac{4}{9}+\frac{2}{9})$

$B(1)=-\frac{2}{3}i+\frac{1}{3}j+\frac{2}{3}k$

$B(1)=\frac{1}{3}$

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3 years ago

Let the sample be 11, 3, 4, 3, 5, 7, 8, 12. What is the range of the sample?

grin007 [14]

Solution

- The Range of a dataset is simply the difference between the largest number and the smallest number in the dataset.

- In the dataset given, the largest number is 12 while the smallest number is 3.

- Thus, the Range of the dataset is

$12-3=9$

Range = 9

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1 year ago

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3 years ago

What is 14 1/4 minus 6 4/5​

What is 14 1/4 minus 6 4/5