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2 years ago

HELP ME I NEED HELP LIKE RIGHT NOW OH GOSH

Mathematics

1 answer:

nataly862011 [7]2 years ago

7 0

Answer:

Step-by-step explanation:

is this in a test

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Is 4 to 7 the same as 7 to 4 explain why it why not

tino4ka555 [31]

It’s not the same because if you simplify them there going to end up looking different (the answers) And they get a whole different do you denominator a numerator

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3 years ago

A rug is to fit in a room so that a border of consistent width is left on all four sides. If the room is 15 ft by 25 ft and the

AlladinOne [14]

Answer: Option 'a' is correct.

Step-by-step explanation:

Since we have given that

Dimensions of the room is given by

15 ft by 25 ft

Let x be the width around the rug.

So, new length = 15-2x

new breadth = 25-2x

Since Area of the rug = 264 sq. ft

So, it becomes,

$\text{Area of rug}=Length\times breadth\\\\264=(15-2x)(25-2x)\\\\264=375-30x-50x+4x^2\\\\264=375-80x+4x^2\\\\4x^2-80x+375-264=0\\\\4x^2-80x+111=0\\\\x=\dfrac{3}{2}\ or\ x=\dfrac{37}{2}\\\\x=1.5\ ft$

Hence, Option 'a' is correct.

4 0

3 years ago

The Sea Dragon, a pendulum ride at an amusement park, moves from its central position at rest according to the trigonometric fun

liubo4ka [24]

Answer:T = 2*Pi / (Pi / 3) = 6 seconds

Step-by-step explanation:

5 0

3 years ago

Show that if the vector field F = Pi + Qj + Rk is conservative and P, Q, R have continuous first-order partial derivatives, then

olchik [2.2K]

Answer:

It is proved that $\frac{\partial P}{\partial y}=\frac{\partial Q}{\partial x}, \frac{\partial P}{\partial z}=\frac{\partial R}{\partial x}, \frac{\partial Q}{\partial z}=\frac{\partial R}{\partial y}$

Step-by-step explanation:

Given vector field,

$F=P\uvec{i}+Q\uvec{j}+R\uvec{k}$

Where,

$P=f_x=\frac{\partial f}{\partial x}, Q=f_y=\frac{\partial f}{\partial y}, R=f_z=\frac{\partial f}{\partial z}$

To show,

$\frac{\partial P}{\partial y}=\frac{\partial Q}{\partial x}, \frac{\partial P}{\partial z}=\frac{\partial R}{\partial x}, \frac{\partial Q}{\partial z}=\frac{\partial R}{\partial y}$

Consider,

$\frac{\partial P}{\partial y}=\frac{\partial}{\partial y}(\frac{\partial f}{\partial x})=\frac{\partial^2 f}{\partial y\partial x}=\frac{\partial^2 f}{\partial x\partial y}=\frac{\partial }{\partial x}(\frac{\partial f}{\partial y})=\frac{\partial Q}{\partial x}$

$\frac{\partial P}{\partial z}=\frac{\partial}{\partial z}(\frac{\partial f}{\partial x})=\frac{\partial^2 f}{\partial z\partial x}=\frac{\partial^2 f}{\partial x\partial z}=\frac{\partial }{\partial x}(\frac{\partial f}{\partial z})=\frac{\partial R}{\partial x}$

$\frac{\partial Q}{\partial z}=\frac{\partial}{\partial z}(\frac{\partial f}{\partial y})=\frac{\partial^2 f}{\partial z\partial y}=\frac{\partial^2 f}{\partial y\partial z}=\frac{\partial}{\partial y}(\frac{\partial f}{\partial z})=\frac{\partial R}{\partial y}$

Hence proved.

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3 years ago

NEED HELP ASAP!!!!!!!!!!!!!!!|

Effectus [21]

Answer:

-3X

Step-by-step explanation:

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3 years ago