Using scientific notation, it is found that:
67 ns = 
s
<h3>What is scientific notation?</h3>
A number in scientific notation is given by:
With the base being 
.
In this problem, the amount is of 67 ns.
Each ns has 
seconds, hence:
We want the base between 1 and 10(exclusive), hence, we move the decimal digit one digit to the left and add one to the exponent, and the representation is:
67 ns = s
You can learn more about scientific notation at brainly.com/question/16394306
Answer:
B. 
Step-by-step explanation:
The lateral area of the right cylinder refers to the curved surface area.
The lateral area of the right cylinder does not include the two circular bases.
The lateral area is given by the formula;
The correct choice is B.
The first step to solving this is to remember our mathematical rules. They state that when the term has a coefficient of -1,, the number doesn't have to be written but the sign needs to remain. This will change the expression to the following:
x - v + 4 + 7y - 3
Now subtract the numbers 4 and 3 from each other.
x - v + 1 + 7y
Since this expression cannot be simplified any further,, the correct answer to your question would be x - v + 1 + 7y.
Let me know if you have any further questions.
:)
Answer:
c on edg
Step-by-step explanation:
18. If f(x)=[xsin πx] {where [x] denotes greatest integer function}, then f(x) is:
since x denotes the greatest integers which could the negative or the positive values, also x has a domain of all real numbers, and has no discontinuous point, then x is continuous in (-1,0).
Answer: B]
20. Given that g(x)=1/(x^2+x-1) and f(x)=1/(x-3), then to evaluate the discontinuous point in g(f(x)) we consider the denominator of g(x) and f(x). g(x) has no discontinuous point while f(x) is continuous at all points but x=3. Hence we shall say that g(f(x)) will also be discontinuous at x=3. Hence the answer is:
C] 3
21. Given that f(x)=[tan² x] where [.] is greatest integer function, from this we can see that tan x is continuous at all points apart from the point 180x+90, where x=0,1,2,3....
This implies that since some points are not continuous, then the limit does not exist.
Answer is:
A]
