For lines to be perpendicular their slopes must be negative reciprocals of one another, mathematically:
m1*m2=-1
So we first need to find the slope of the reference line.
m=(y2-y1)/(x2-x1)=(7-2)/(-1--5)=5/4
So the perpendicular line will have a slope of:
5m/4=-1
m=-4/5
So our perpendicular line so far is:
y=-4x/5+b, now we can use point (3,-1) to solve for the y-intercept, "b"
-1=-4(3)/5+b
-1=-12/5+b
-5/5+12/5=b
7/5=b
So the line is:
y=-4x/5+7/5 or more neatly
y=(-4x+7)/5
y=-0.8x+1.4
Answer:
0.67 = x
Step-by-step explanation:
to solve the value of x we need to : (x,9)
y = 3x + 7
9 = 3x + 7
9 - 7 = 3x
2 = 3x
2/3 = x
0.67 = x
Answer:
The answer is D
You have to distribute the x to the 2x + 3 equation
This will result in 2x^2 + 3x
72.22 I think I’m sorry if I’m wrong
Answer:
x=4.5.
The slope is undefined. Thus the y variable is irrelevant. It appears as though the line crosses through 4.5 on the x axis making the equation
x = 4.5
