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ddd [48]
3 years ago
6

Will Name Brainliest!!!!!!! :)

Mathematics
2 answers:
Gnoma [55]3 years ago
5 0

Answer: C) 3

Explanation:  

Point A is located at (0,2). It moves to A ' (0,6). Focus on the y coordinates. We go from y = 2 to y = 6. This is a jump of multiplying by 3. We have multiplied every coordinate of A by 3 to get corresponding coordinates for A'.

Point B will be treated the same way. It starts off at B = (2,3) and moves to B ' = (6,9) after multiplying both coordinates by the same scale factor 3.

The length of AB will also be tripled

length of A'B' = 3*(length of AB)

Len [333]3 years ago
3 0

A' (0,4) respuesta es

espero que te sirva marcarme como mejor respuesta PORFA y gracias

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FG ∥ CB, A ∈ FG, D ∈ AB, E ∈ AC
andrey2020 [161]

Answer:

The value of x is 31^{\circ}.

Step-by-step explanation:

Please look at the figure attached to get more clear solution.

We have given:

FG||CB

And the line that cut the parallel line is transversal so, here BA is transversal

And alternate interior angles on transverse line are equal

So, ∠1=∠4

And ∠4=28^{\circ}

Hence,  ∠1=∠4=28^{\circ}

And On FG the sum of angles will be 180^{\circ}

∠3+∠2+∠1=180^{\circ}

90^{\circ}+∠2+28^{\circ}=180^{\circ}

Hence, ∠2=62^{\circ}

Now, we know that the sum of interior angles is equal to the exterior angle:

Therefore, ∠2+∠5=∠6+∠7

62^{\circ}+3x=x+4x

On simplification we get:

2x=62^{\circ}

x=31^{\circ}

Hence, the value of x is 31^{\circ}.

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