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3 years ago

The Toys of Life store had 240 customers on October 24th. They had 264 customers on

Mathematics

1 answer:

Scorpion4ik [409]3 years ago

4 0

Answer:

Step-by-step explanation:

I think its 24 because 64÷20=40

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If 7x+2y =3 and x-3y=30, what is the value of y?

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Answer:

-9

Step-by-step explanation:

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2 years ago

a flour company in minneapolis wants to know what percent of local households bake at least twice a week. A company representati

seropon [69]

Answer:

Step-by-step explanation:

The response of this would be to say that those people without daytime jobs that are outside the home, are more likely to be home and thus, have more time on their hands to attempt to bake. So basically, the quoted 56% is definitely going to be higher than the population percentage.

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3 years ago

Write the population of lubbok in word form

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1651384 also known as "one million, six hundred fifty one thousand, three hundred eighty four"

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3 years ago

A growth-mindset researcher plans to take an SRS of 200 teenagers from the population of teenagers in North America to see what

Sonbull [250]

Answer:

The mean of the sampling distribution of p is 0.75 and the standard deviation is 0.0306.

Step-by-step explanation:

Central Limit Theorem:

For a proportion p in a sample of size n, the sampling distribution of the sample proportion will be approximately normal with mean $\mu = p$ and standard deviation $s = \sqrt{\frac{p(1-p)}{n}}$

75% of teenagers in North America are pursuing a goal they have set for themselves.

This means that $p = 0.75$

Sample of 200.

This means that $n = 200$ .

What are the mean and standard deviation of the sampling distribution of p?

By the Central Limit Theorem

Mean $\mu = p = 0.75$

Standard deviation $s = \sqrt{\frac{0.75*0.25}{200}} = 0.0306$

The mean of the sampling distribution of p is 0.75 and the standard deviation is 0.0306.

4 0

3 years ago

Which value is NOT a solution of 8x3 – 1 = 0?

Tpy6a [65]

Note: As you may have unintentionally missed to add the value choices. But, I would make sure to explain the concept so that you may improve your understanding in terms of solving these type of questions.

Answer:

Any value other than the values $x=\frac{1}{2},\:x=-\frac{1}{4}+i\frac{\sqrt{3}}{4},\:x=-\frac{1}{4}-i\frac{\sqrt{3}}{4}$ will not be a solution of $8x^3\:-\:1\:=\:0$ .

Step-by-step explanation:

Considering the equation

$8x^3\:-\:1\:=\:0$

Steps to solve the equation

$8x^3-1=0$

$\mathrm{Add\:}1\mathrm{\:to\:both\:sides}$

$8x^3-1+1=0+1$

$\mathrm{Simplify}$

$x^3=\frac{1}{8}$

$\mathrm{Divide\:both\:sides\:by\:}8$

$\frac{8x^3}{8}=\frac{1}{8}$

$\mathrm{Simplify}$

$x^3=\frac{1}{8}$

$\mathrm{For\:}x^3=f\left(a\right)\mathrm{\:the\:solutions\:are\:}x=\sqrt[3]{f\left(a\right)},\:\sqrt[3]{f\left(a\right)}\frac{-1-\sqrt{3}i}{2},\:\sqrt[3]{f\left(a\right)}\frac{-1+\sqrt{3}i}{2}$

$x=\sqrt[3]{\frac{1}{8}},\:x=\sqrt[3]{\frac{1}{8}}\frac{-1+\sqrt{3}i}{2},\:x=\sqrt[3]{\frac{1}{8}}\frac{-1-\sqrt{3}i}{2}$

So,

$x=\frac{1}{2},\:x=-\frac{1}{4}+i\frac{\sqrt{3}}{4},\:x=-\frac{1}{4}-i\frac{\sqrt{3}}{4}$

Therefore,

Any value other than the values $x=\frac{1}{2},\:x=-\frac{1}{4}+i\frac{\sqrt{3}}{4},\:x=-\frac{1}{4}-i\frac{\sqrt{3}}{4}$ will not be a solution of $8x^3\:-\:1\:=\:0$ .

Keywords: solution, value

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7 0

2 years ago