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2 years ago

11

2) -7x + 5y=10 4x - 5y=-10

2 answers:

lianna [129]2 years ago

8 0

-7x+5y=10

4x-5y=-10

Find x first by eliminating the y.

Add the two equations together.

-7x+4y=-3y

+5y-+5y= 5y-5y=0

10-+10=0

-3x=0

divide both sides by -3

-3x/-3=0/-3

x=0

Find y by using x=0 into -7x+5y=10 ( using substitution method)

-7(0)+5y=10

0+5y=10

5y=10

divide both sides by 5

5y/5=10/5

y=2

Answer:

(0,2)

bezimeni [28]2 years ago

5 0

To solve this, the problem is solvable by elimination. So you see how the 5y and -5y cancel out? You basically add those two and you add the -7x and 4x and 10 and -10 leaving you with -3x=0. Dividing by each side gives you x=0. Then, plug 0 in for x in -7x+5y=10. Giving you

-7(0)+5y=10.

0+5y=10

5y=10
Divide by 5 on each side giving you y=2. So your answer is (0,2).

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What is the solutions to 0=x^2-x-6<br> two things <br> ,,quadratic equationz,,,

natita [175]

Answer:

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Step-by-step explanation:

$x = \frac{ - b + - \sqrt{b {}^{2} - 4ac } }{2a}$

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3 0

2 years ago

Two large and 1 small pumps can fill a swimming pool in 4 hours. One large and 3 small pumps can also fill the same swimming poo

kolezko [41]

Let <em>x</em> and <em>y</em> be the unit rates at which one large pump and one small pump works, respectively.

Two large/one small operate at a unit rate of

(1 pool)/(4 hours) = 0.25 pool/hour

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2<em>x</em> + <em>y</em> = 0.25

One large/three small operate at the same rate,

(1 pool)/(4 hours) = 0.25 pool/hour

<em>x</em> + 3<em>y</em> = 0.25

Solve for <em>x</em> and <em>y</em>. We have

<em>y</em> = 0.25 - 2<em>x</em> ==> <em>x</em> + 3 (0.25 - 2<em>x</em>) = 0.25

==> <em>x</em> + 0.75 - 6<em>x</em> = 0.25

==> 5<em>x</em> = 0.5

==> <em>x</em> = 0.1

==> <em>y</em> = 0.25 - 2 (0.1) = 0.25 - 0.2 = 0.05

In other words, one large pump alone can fill a 1/10 of a pool in one hour, while one small pump alone can fill 1/20 of a pool in one hour.

Now, if you have four each of the large and small pumps, they will work at a rate of

4<em>x</em> + 4<em>y</em> = 4 (0.1) + 4 (0.05) = 0.6

meaning they can fill 3/5 of a pool in one hour. If it takes time <em>t</em> to fill one pool, we have

(3/5 pool/hour) (<em>t</em> hours) = 1 pool

==> <em>t</em> = (1 pool) / (3/5 pool/hour) = 5/3 hours

So it would take 5/3 hours, or 100 minutes, for this arrangement of pumps to fill one pool.

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