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BigorU [14]
3 years ago
11

2) -7x + 5y=10 4x - 5y=-10

Mathematics
2 answers:
lianna [129]3 years ago
8 0

-7x+5y=10

4x-5y=-10

Find x first by eliminating the y.

Add the two equations together.

-7x+4y=-3y

+5y-+5y= 5y-5y=0

10-+10=0

-3x=0

divide both sides by -3

-3x/-3=0/-3

x=0

Find y by using x=0 into -7x+5y=10 ( using substitution  method)

-7(0)+5y=10

0+5y=10

5y=10

divide both sides by 5

5y/5=10/5

y=2

Answer:

(0,2)

bezimeni [28]3 years ago
5 0
To solve this, the problem is solvable by elimination. So you see how the 5y and -5y cancel out? You basically add those two and you add the -7x and 4x and 10 and -10 leaving you with -3x=0. Dividing by each side gives you x=0. Then, plug 0 in for x in -7x+5y=10. Giving you

-7(0)+5y=10.

0+5y=10

5y=10
Divide by 5 on each side giving you y=2. So your answer is (0,2).

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Hey There,

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Multiply across

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Given:

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To find:

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From 11 positive integer scores on a 10-point quiz, the mean is exactly 8, the median is exactly 8, and the mode is exactly 7. f
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<span>3 perfect scores of 10 There can't be 5x10 because the mode (the commonest score) is 7. Hence if there are 5x10 there must be 6 x7, but the median (the middle score) is 8 and this would make at least 12 scores which is impossible. There can't be 4x10. If there were 4 x10 there would be 5x7 (7=mode), 1x8(median) + either another 8 or 9. Assuming the best case scenario (2 x8). The total of the 11 scores = 91. They should add up to 88 (mean = 8, (11x8=88) If there are 3x10, there must be at least 4x7(mode =7), 3more 8+(median = 8), and 1 x less than 7. 3x10, 3x8, 4x7 and 1x6 fits the bill. Mean= (30+24+28+6)/11 = 88/11 = 8 OK Median is the sixth number in the series = 8 OK The mode is the commonest number. Mode = 7 OK</span>
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