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Umnica [9.8K]
3 years ago
9

Evaluate the expression. -x^2 -4x: x =. -3

Mathematics
1 answer:
Ierofanga [76]3 years ago
7 0
Substitute the x-value into the expression and solve it. -x^{2} - 4x Substitute all the x variables for 3 -3^{2} - 4(3) Use PEMDAS and start with the exponent (-3^{2} = -3 x -3 = 9) 9 - 4(3) Multiply 9 - 12 Subtract -3
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Determine the center and radius of the following circle equation:<br> x2 + y2 – 10x + 8y + 40 = 0
antiseptic1488 [7]

Answer:

The center of this circle is (5, -4) and the radius is 1.

Step-by-step explanation:

First regroup these terms according to x and y :

x^2 - 10x + y^2 + 8y = -40

Next, complete the square for x^2 - 10x:  x^2 - 10x + 5^2 - 5^2.

and the same for y^2 + 8y:  y^2 + 8y + 16 - 16

Substituting these results into x^2 - 10x + y^2 + 8y = -40, we get:

x^2 - 10x + 5^2 - 5^2 y^2 + 8y + 16 - 16 = -40.

Next, rewrite x^2 - 10x + 25 and y^2 + 8y + 16 as squares of binomials:

Then x^2 - 10x + 5^2 - 5^2 y^2 + 8y + 16 - 16 = -40 becomes:

(x - 5)^2 + (y + 4)^2 - 25 - 16 = -40, or:

(x - 5)^2 + (y + 4)^2 = 1

This equation has the form (x - h)^2 + (y - k)^2 = r^2, where (h, k) is the center and r is the radius.  Matching like terms, we get h = 5, k = -4 and r = 1.

The center of this circle is (5, -4) and the radius is 1.

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3 years ago
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Starting at the same point, Joe and Anita go roller blading in opposite directions. If Joe roller blades at a speed of 4 mph, an
agasfer [191]

Answer:

They will be at a distance of 16 miles apart from each other.

Step-by-step explanation:

Both Joe and Anita start roller balding in opposite directions, and both of them have the same speed of 4 mph.

As they move oppositely in a straight line therefore, the distance between them will be the distance travelled by each of them's sum.

Distance covered by Joe in 2 hours= 8 miles

Distance covered by Anita in 2 hours= 8 miles

Therefore, the total distance from each other =16 miles

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Nesterboy [21]

Answer:

just do

Step-by-step explanation:

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Answer:

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by doing 3n so 8-3n is your anwser...

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