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defon
3 years ago
8

Suppose your parents started saving for your college education when you were 5 years old. Assume they saved $300 the first year,

$325 the second year, $350 the third year, and so on increasing each year contribution by $25 if you are 17 in the last year of contribution how much will have been saved in all ?
Mathematics
1 answer:
Aleonysh [2.5K]3 years ago
3 0

Answer:

5850

Step-by-step explanation:

300+25x

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Find the distance, c, between (–3, 4) and (2, –3) on the coordinate plane. Round to the nearest tenth if necessary.
andriy [413]

Using the distance formula, the distance between (-3, 4) and (2, -3) is: 8.6 units.

<h3>What is the distance formula?</h3>

Distance formula for calculating the distance between two points on a coordinate plane is given as: d = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2}.

Let,

(-3, 4) = (x1, y1)

(2, -3) = (x2, y2)

Plug in the values

c = \sqrt{(2 - (-3))^2 + (-3 - 4)^2} \\\\c = \sqrt{74} \\\\

c = 8.6 units.

Therefore, using the distance formula, the distance between (-3, 4) and (2, -3) is: 8.6 units.

Learn more about distance formula on:

brainly.com/question/661229

5 0
2 years ago
Simplify.
Alenkasestr [34]
Answer is <span>C) 1/4^2
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7 0
3 years ago
PLEASE HELP ASAP!!!! GOING TO GIVE 30 POINTS
fomenos

Answer:

The second answer option

Step-by-step explanation:

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5 0
3 years ago
The total cost of painting of four walls of a square hall at Rs. 40 per sq. m. is Rs. 12000. If the hall contains 600 m³ of air,
astra-53 [7]

Answer:

The height of the hall is 9.375 meters

Step-by-step explanation:

The rate at which the walls of the square hall are painted, R = Rs. 40 per sq. m.

The total cost of painting the square hall, C = Rs. 12,000

The volume of air contained in the hall, V = 600 m³

The surface area of the four walls of the hall, A = C/A

∴ A = Rs. 12,000/(Rs. 40/m²) = 300 m²

Let 's' represent the length of sides of the square hall, and let 'h' represent the height of the square wall, we have;

The volume of the hall, V = s² × h

The surface area of the wall, A = 4 × s × h

Therefore, we get;

A = 300 = 4 × s × h

V = 600 = s² × h

V/A = 600/300 = 2 = s² × h/(4 × s × h) = s/4

s/4 = 2

s = 4 × 2 = 8

The side length of the square hall, s = 8 m.

From the area, A = 4 × s × h, we get;

A = 300 = 4 × 8 × h

h = 300/(4 × 8) = 9.375

The height of the hall, h = 9.375 m.

8 0
3 years ago
PLEASE HELP - image attachment below, thanks! :)
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2 years ago
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