Wait and be patience for the medication, it could take some more time in certain cases
Answer:
The correct answer is - 1/41,493
Explanation:
Let assume the frequency of the two possible same allele genotype (dominant and recessive) in an inbred population is p and q. Then the frequency of heterozygotes (H) is denoted as:
2pq + 2pqF. ( where F is the inbreeding coefficient).
The frequency of the two different hoozygotes in inbred population can be calculated as:
p2 + pqF and q2 + pqF. (Where p and q are the allele frequency of the dominant and recessive phenotype.
Given: Frequency of Alkaptonuria (q 2) = 1:500, 000
=> q = 1/707
p = 706/707 ( Approx values)
solution:
Inbreeding coefficient (F) = 1/64
Therefore,
Frequency of Alkaptonuria in second cousins= q 2 + pqF
= 1/500, 000 + (706/707 x 1/707) x (1/64)
= 1/500, 000 + 1/45, 248
= 1/41,493 (approx)
The last one is the correct answer
Answer:
Only a. DNA comparisons of dogs and wolves is valid evidence.
Explanation:
Answer:
-"I can add cheese to sandwiches or snacks."
-"I can supplement puddings and cereals with Ensure."
Explanation:
The patient need to eat the food that makes her gain weight and avoid malnutrition. In the supplementation, its is important that the patient eats the diet that not only promotes weight gain, but supply the essential nutrients needed by the body. Thus, cheese is known to contain the fat from the milk that provides supplemental energy to the body. In addition, the patient needs to reduce the consumption of instant foods and consider nutritious foods. Thus, she can supplement puddings and cereals with Ensure. These interventions result in weight gain.
