Answer:
a) The genes present on separate chromosomes exhibit indepedent assortment.
b) The genotype of tall and purple flower parent= TTPp
The genotype of short and purple flower parent: ttPp
Explanation:
a) In a dihybrid cross, if the genes are present on the same chromosome, they will not exhibit independent assortment. The genes present on the same chromosome are called linked genes. Linked genes are inherited together. The absence of independent assortment of a linked gene gives more of parental types in F2 progeny. Therefore, if genes are not present on a separate chromosome, Mendel’s ratios deviate.
b) Alleles for tallness and purple flower are dominant. In the progeny, all the plants are tall. This means that the dominant tall plant is homozygous. With respect to flower color, the trait exhibits segregation of dominant and recessive alleles and both purple and white flower progeny are obtained. This makes both the plants heterozygous for the flower color gene.
The genotype of tall and purple flower parent= TTPp
The genotype of short and purple flower parent: ttPp
Answer:the answer is
The protein would be incorrect and the protein might not function
Answer: Option A) A-C-T-T-G
Explanation:
The base sequence on a strand of DNA is usually paired to specific complimentary bases. These specific pairings are as follows:
Adenine (A) pairs with Thymine (T)
Guanine (G) pairs with Cytosine (C). So when you find A replace with T, so also replace C with G and vice versa.
Thus, the complimentary sequence of the T-G-A-A-C DNA strand is A-C-T-T-G
C. Hinge is the correct answer your welcome
Answer:
c
Explanation:
Random distribution of the Isopods should be 50/50 in A and B.
Chi-square =
where O = observed frequency and E = expected frequency
Chamber O E Chi-square
A 18 10
= 6.4
B 2 10
= 6.4
<em>Total Chi-square </em>= 6.4 + 6.4 = 12.8
<em>Degree of freedom</em> = 2 - 1 = 1
<em>Tabulated Chi-square</em> (α = 0.05) = 3.8415
The calculated Chi-square exceeds the critical value, hence, it is significant and not due to random.
<em>The correct option is </em><em>c</em><em>.</em>