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cluponka [151]
3 years ago
12

Andy drew a regression line for this paired data set .

Mathematics
2 answers:
Genrish500 [490]3 years ago
6 0

D ,

make sure to thank me!


IgorC [24]3 years ago
3 0

just took the test the answer is actually

c)  y= 5.5x+52





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The shape will shrink
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To help divide a group into 4 teams, the teacher brought out a bag with equal numbers of 4 different colored popsicle sticks (gr
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The set of all possible events Ω

Ω = 24 ( 4*7 = 28 stick)

<span>set of events favorable A
A = 7 ( </span><span>sticks of green is 7)

</span><span>Probability P
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3 years ago
What is the name of a shape with two parallel sides and four right angles
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A square has two parallel sides and four right angles.
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Samples of rejuvenated mitochondria are mutated (defective) in 3% of cases. Suppose 15 samples are studied, and they can be cons
stiks02 [169]

Answer:

C) At most one sample is mutated

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If there are 15 samples, it means that 15 is the total (100%) of samples. Then, if we know that there is a chance that 3% are mutated, then we calculate the 3% of 15:

Mutated= \frac{3. 15}{100} = 0.45

This means that at most one sample is mutated, as this result is not zero (we discard answer A), and 0.45 is not more than half of the samples.

5 0
3 years ago
The area of sector A08 is 48x and m&lt;AOB = 270º. Find the radius of circle O.
Softa [21]

Answer:

Step-by-step explanation:

The first one gives us everything we need except the radius, which is easy enough to solve for if you're careful with your algebra. The area of a sector of a circle is given as:

A_s=\frac{\theta}{360}*\pi r^2 where θ is the measure of the central angle of the circle. For us, that fills in as follows:

48\pi=\frac{270}{360}*\pi r^2 and manipulate it as follows:

r^2=\frac{(360)(48\pi)}{270\pi} the π's cancel out, leaving us with simple multiplication and division to get

r = 8. Now for the next one, which is a bit more involved.

In order to find the area of the shaded part, we need to find the area of the right triangle there and subtract it from the area of the sector of the circle. First the area of the sector, which is given as:

A_s=\frac{\theta}{360}*\pi r^2 where θ again is the measure of the central angle of the circle, 90°:

A_s=\frac{90}{360}(3.1415)(10)^2 which simplifies a bit to

A_s=\frac{1}{4}(3.1415)(100), giving us an area of

A_s=78.5375m^2. Now onto the area of the triangle.

Since this triangle is inscribed in the circle and the circle's radius is 10, tha also gives us both the height and the base measures of the triangle. The area then is:

A_t=\frac{1}{2}(10)(10) which is

A_t=50m^2

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4 0
3 years ago
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