Answer:
Step-by-step explanation:
The centroid of a triangle always cuts a triangle perfectly at 2/3.
What I mean by this is that the line that touches the tip of the triangle and touches the median of the base is cut into one third and its other part is cut into two thirds of the whole segment. This segment is AY.
Knowing this, I can tell that OY is 1/3 of the length of AO, which is given to be 12.7 m.
To find OY, make an equation where AO and OY add up to AY.
The variable x represents the length of AY, and 1/3x represents the length of OY (because it is one-third of AY).
Solve the equation by subtracting 1/3x from both sides.
Divide both sides by 2/3.
Now we know the length of AY (x). To find the length of OY substitute this value of x into 1/3x, which represents OY.
This gives us 6.35, which is the length of OY.
The final answers are:
the answer is... 5≥ 4x-2.5!! I hope this helps. Or do u need what x stands for?
Actually there are three types of construction that were never accomplished by Greeks using compass and straightedge these are squaring a circle, doubling a cube and trisecting any angle.
The problem of squaring a circle takes on unlike meanings reliant on how one approaches the solution. Beginning with Greeks Many geometric approaches were devised, however none of these methods accomplished the task at hand by means of the plane methods requiring only straightedge and a compass.
The origin of the problem of doubling a cube also referred as duplicating a cube is not certain. Two stories have come down from the Greeks regarding the roots of this problem. The first is that the oracle at Delos ordered that the altar in the temple be doubled over in order to save the Delians from a plague the other one relates that king Minos ordered that a tomb be erected for his son Glaucus.
The structure of regular polygons and the structure of regular solids was a traditional problem in Greek geometry. Cutting an angle into identical thirds or trisection was another matter overall. This was necessary to concept other regular polygons. Hence, trisection of an angle became an significant problem in Greek geometry.
If one inch equals 25.4 millimeters, you would have to divide 25.4 by 1/8 which equals to 3.2 (3.175 before rounding). Subtract 3.2 from 25.4 = 22.2 millimeters
The value of x is more 90 because the angle is an obtuse and an obtuse is more than 90 degrees.
