-0.6 into a fraction

DeVondrea stacked 2

Evgen [1.6K]

Answer:

Step-by-step explanation:

Number of nickels = $1 * 1 nickel/$0.05 = 20 nickels

Thickness of 20 nickels = 20 nickels * 1.95 mm = 39 mm

Let's do the same for the quarters. Each quarter is worth $0.25.

Number of quarters = $1 * 1 quarter/$0.25 = 4 quarters

Thickness of 4 quarters = 4 quarters * 1.75 mm = 7 mm

Find the ratio of the two:

39 mm/7 mm = 5.57

8 0

2 years ago

I am greater than 50 and less than 55. the sum of my digits is 8. what number am i

valentinak56 [21]

Answer:

53

Step-by-step explanation:

6 0

3 years ago

Read 2 more answers

How many pairs of parallel does a trapoziod have?

Leviafan [203]

1 pair of sides are parallel in a trapezoid

3 0

3 years ago

The numbers represented by variables w and y on the number line are integers.

mixas84 [53]

Option A) when y=6 and w= 2, Option B) when y=4 and w=-1 are the TWO correct choices.

Step-by-step explanation:

The given inequality is w<x<y and x>2.

step 1: let us assume that x=3, since it is given that x>2.

step 2: substitute the value of x=3 and each options in the inequality

step 3: option A) w=2, y=6. Then w<x<y = 2<3<6 (the condition satisfies).

option B) w= -1, y=4. Then w<x<y = -1<3<4 (the condition satisfies).

option C) w= 0, y=2. then w<x<y ≠ 0<2<2 (does not satisfies).

option D) w= -2, y=0. then w<x<y ≠ -2<2<0 (does not satisfies).

option E) w= -4, y= -1. then w<x<y ≠ -4<2<-1 (does not satisfies).

5 0

3 years ago

Write a formula that shows the dependence of: the length of the side (a) of a cube on the surface area (S) of the cube

Natali5045456 [20]

Answer:

Let a = side length of a cube

Let S = surface area of a cube

Area of a square = a²

Since a cube has 6 square sides: S = 6a²

To make a the subject:

S = 6a²

Divide both sides by 6:

$\sf \implies \dfrac{S}{6}=a^2$

Square root both sides:

$\sf \implies a=\sqrt{\dfrac{S}{6}}$

(positive square root only as distance is positive)

-----------------------------------------------------------------------------------------------

$\sf x=-3-\sqrt{2} \implies (x+[3+\sqrt{2}])=0$

$\sf x=-3+\sqrt{2} \implies (x+[3-\sqrt{2}])=0$

Therefore,

$\sf y=a(x+[3+\sqrt{2}]) (x+[3-\sqrt{2}])$ for some constant a

Given the y-intercept is at (0, -5)

$\sf \implies a(0+3+\sqrt{2}) (0+3-\sqrt{2})=-5$

$\sf \implies a(3+\sqrt{2}) (3-\sqrt{2})=-5$

$\sf \implies a(9-2)=-5$

$\sf \implies 7a=-5$

$\sf \implies a=-\dfrac57$

Substituting found value of a into the equation and simplifying:

$\sf y=-\dfrac57(x+[3+\sqrt{2}]) (x+[3-\sqrt{2}])$

$\sf \implies y=-\dfrac57(x^2+6x+7)$

$\sf \implies y=-\dfrac57x^2-\dfrac{30}{7}x-5$

3 0

2 years ago