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FromTheMoon [43]
3 years ago
11

Math question? It is #13.

Mathematics
2 answers:
Effectus [21]3 years ago
7 0
d,
If you change the y-intercept but keep the slope the same, it just moves the line up or down. Since the lines would have the same slope (same rate of change), the two lines would be parallel.

AnnZ [28]3 years ago
3 0

d,

If you change the y-intercept but keep the slope the same, it just moves the line up or down. Since the lines would have the same slope (same rate of change), the two lines would be parallel.

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Looking at the first system of equations,

16x - 10y = 10

-8x - 6y = 6

If we multiply both sides of the second equation by 2, the coefficient of x is exactly the negative of the coefficient of x in the first equation.

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By combining this new equation with the first one, we can eliminate x and solve for y :

(16x - 10y) + (-16x - 12y) = 10 + 12

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16x - 10y = 10

⇒   16x - 10 (-1) = 10

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⇒   16x = 0

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The main idea behind elimination is combining the given equations in just the right amount so that one of the variables disappears. The "right amount" involves using the LCM of the coefficients of a given variable. In this example, the x-coefficients had LCM(8, 16) = 16, so we only had to scale one of the equations (the one with -8x) to cancel all the x terms.

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16x - 10y = 10

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-8x - 6y = 6

⇒   -5 (-8x - 6y) = -5 (6)

⇒   40x + 30y = -30

Now combining the two scaled equations gives

(48x - 30y) + (40x + 30y) = 30 + (-30)

⇒   88x = 0

⇒   x = 0

We then solve for y :

16x - 10y = 10

⇒   -10y = 10

⇒   y = -1

so we end up with the same solution as before.

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