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ch4aika [34]
4 years ago
13

21 = 1/4x what is x.

Mathematics
2 answers:
galina1969 [7]4 years ago
7 0

Answer:

84

Step-by-step explanation:

Hello there!

We could solve this with an equation, but just think about it. The given expression shows that 21 is 1/4 of x. So just multiply 21 by 4 and get 84.

;)

Kay [80]4 years ago
3 0
The answer is x=84
I typed it into desmos
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Gymnast clothing manufactures expensive soccer cleats for sale to college bookstores in runs of up to 500. It's cost (in dollars
NeTakaya

Revenue, R = 130x


Profit, P = Revenue – Cost


 P = R – C


P = 130x – 2950 + 6x + 0.1x^2


At P = 0


0 = -2950 + 136x +0.1x^2


X = 21.355, -1381.355


Therefore, manufacture greater than 21.355 items to make

profit. 

6 0
4 years ago
If α and β are the zeroes of the polynomial 6y 2 − 7y + 2, find a quadratic polynomial whose zeroes are 1 α and 1 β .
ollegr [7]

Answer:

2y^2-7y+6=0

Step-by-step explanation:

We are given that \alpha and \beta are the zeroes of the polynomial 6y^2-7y+2

y^2-\frac{7}{6}y+\frac{1}{3}

We have to find a quadratic polynomial whose zeroes are 1/\alpha and 1/\beta.

General quadratic equation

x^2-(sum\;of\;zeroes)x+ product\;of\;zeroes

We get

\alpha+\beta=\frac{7}{6}

\alpha \beta=\frac{1}{3}

\frac{1}{\alpha}+\frac{1}{\beta}=\frac{\alpha+\beta}{\alpha \beta}

\frac{1}{\alpha}+\frac{1}{\beta}=\frac{7/6}{1/3}

\frac{1}{\alpha}+\frac{1}{\beta}=\frac{7}{6}\times 3=7/2

\frac{1}{\alpha}\times \frac{1}{\beta}=\frac{1}{\alpha \beta}

\frac{1}{\alpha}\times \frac{1}{\beta}=\frac{1}{1/3}=3

Substitute the values

y^2-(7/2)y+3=0

2y^2-7y+6=0

Hence, the quadratic polynomial whose zeroes are 1/\alpha and 1/\beta is given by

2y^2-7y+6=0

4 0
4 years ago
Is the number there three? if you answer to me i will give you twenty Points.
juin [17]

Answer:

2

Step-by-step explanation:

3 x 2 = 6

1 x 2 = 2

hope it helps

sorry if I'm wrong

7 0
2 years ago
A spinner is divided into 20 equal sections. what is the probability of the spinner's pointer landing on section 5?
marta [7]
1/20 would be the correct answer
3 0
4 years ago
Read 2 more answers
(3a) (a^-3) please help I'm very confused if possible please show your work! <:D
kupik [55]

\bf ~\hspace{7em}\textit{negative exponents} \\\\ a^{-n} \implies \cfrac{1}{a^n} ~\hspace{4.5em} a^n\implies \cfrac{1}{a^{-n}} ~\hspace{4.5em} \cfrac{a^n}{a^m}\implies a^na^{-m}\implies a^{n-m} \\\\[-0.35em] \rule{34em}{0.25pt}\\\\ (3a)(a^{-3})\implies 3a\cdot \cfrac{1}{a^3}\implies \cfrac{3a}{a^3}\implies \cfrac{3~~\begin{matrix} a \\[-0.7em]\cline{1-1}\\[-5pt]\end{matrix}~~}{aa~~\begin{matrix} a \\[-0.7em]\cline{1-1}\\[-5pt]\end{matrix}~~}\implies \cfrac{3}{a^2}

5 0
3 years ago
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