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11Alexandr11 [23.1K]
4 years ago
15

Simplify 3x^2-10x-8/ x-4

Mathematics
1 answer:
luda_lava [24]4 years ago
5 0
3x³-10x²-4x-8 over x
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WILL GIVE BRAINLYEST
zalisa [80]

Answer:

C

Step-by-step explanation:

Let us factor out the 5:

5*x + 5*2y- 5*3

5(x+2y-3)

Therefore, C

<em>I hope this helps! :)</em>

5 0
3 years ago
Read 2 more answers
What is the coefficient of the x^5y^5- term in the biomial expansion of (2x-3y)^10
jasenka [17]

<u>Answer:</u>

 The coefficient of x^{5} \times y^{5} \text { is }=\left(252 \times 2^{5} \times(-3)^{5}\right)=252 \times 32 \times 243=1959552

<u>Solution: </u>

The given expression is (2 x-3 y)^{10}

As per binomial theorem, we know,

(x+y)^{n}=\sum n C_{k} x^{n-k} y^{k}

Now here a = 2x, b = (- 3y) and n = 10 and k = 0,1,2,….10

Now x^{5}\times y^5 will be the 6 term where k =5

Now, \mathrm{T}_{6}=10 \mathrm{C}_{5} \times(2 \mathrm{x})^{(10-5)} \times(-3 \mathrm{y})^{5}=10 \mathrm{C}_{5} 2^{5} \times \mathrm{x}^{5} \times(-3)^{5} \times \mathrm{y}^{5}

So, the coefficient of x^{5} \times y^{5} \text { is }=10\left(5 \times 2^{5} \times(-3)^{5}\right.

10 \mathrm{C}_{5}=\frac{10 !}{5 ! \times(10-5) !}=\frac{10 !}{5 !+5 !}=\frac{10 \times 9 \times 8 \times 7 \times 6 \times 5 !}{5 ! \times 5 !}=\frac{10 \times 9 \times 8 \times 7 \times 6}{5 \times 4 \times 3 \times 2 \times 1}=\left(\frac{30240}{120}\right)=252

The coefficient of x^{5} \times y^{5} \text { is }=\left(252 \times 2^{5} \times(-3)^{5}\right)=252 \times 32 \times 243=1959552

6 0
4 years ago
Which ratios that are equivalent to 20:12?
n200080 [17]

Step-by-step explanation:

5:6

is your answer.

good morning

have a great day

7 0
3 years ago
For f left parenthesis x right parenthesis equals StartRoot x EndRoot and g left parenthesis x right parenthesis equals 4 x plus
lara31 [8.8K]

Answer:

Step-by-step explanation:

Given that there are two functions f and g as

f(x) = \sqrt{x} \\g(x) =4x+9

We have to find the composition of functions.

Composition functions are calculated as the first function inside bracket and then the outside function of answer inside.

a)fog= f{g(x)} =f(4x+9) = \sqrt{4x+9}

b) gof = g{f(x)} = g(\sqrt{x} )=4\sqrt{x} +9

c) fof = f(\sqrt{x} ) = \sqrt[4]{x}

d) gog = g(4x+9) = 4(4x+9)+9\\= 16x+45

4 0
3 years ago
PLEASE HELP ASAP!!!! 100% CORRECT ANSWERS ONLY PLEASE!!!!
stealth61 [152]
The answer is "alternate exterior angles theorem."
3 0
3 years ago
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