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melomori [17]
3 years ago
8

Can someone please help me please

Mathematics
1 answer:
zhenek [66]3 years ago
6 0
Its 3. the coefficient of y
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Calculus: Help ASAP
Serggg [28]
\bf \displaystyle \int\limits_{-1}^{0}~(4x^6+2x)^3(12x^5+1)\cdot  dx\\\\
-------------------------------\\\\
u=4x^6+2x\implies \cfrac{du}{dx}=24x^5+2\implies \cfrac{du}{2(12x^5+1)}=dx\\\\
-------------------------------\\\\
\displaystyle \int\limits_{-1}^{0}~u^3\underline{(12x^5+1)}\cdot\cfrac{du}{2\underline{(12x^5+1)}}\implies \cfrac{1}{2}\int\limits_{-1}^{0}~u^3\cdot du\\\\
-------------------------------\\\\

\bf \textit{now, we'll change the bounds, using u(x)}
\\\\\\
u(-1)=4(-1)^6+2(-1)\implies u(-1)=2
\\\\\\
u(0)=4(0)^6+2()\implies u(0)=0\\\\
-------------------------------\\\\
\displaystyle \cfrac{1}{2}\int\limits_{2}^{0}~u^3\cdot du\implies \left. \cfrac{1}{2}\cdot \cfrac{u^4}{4}  \right]_{2}^{0}\implies \left. \cfrac{u^4}{8}  \right]_{2}^{0}\implies [0]-[2]\implies -2
5 0
3 years ago
MULTIPLE CHOICE
Dvinal [7]

Step 1) Multiply 2 by 3

<em>5x+6 = 2x+3x+6</em>

Step 2) Combine like terms

<em>5x+6 = 5x+6</em>

Step 3) Add 5x and 6 to both sides

Answer:

<em>0 = 0</em>

4 0
3 years ago
The lifetime of a certain type of TV tube has a normal distribution with a mean of 61 and a standard deviation of 6 months. What
Ad libitum [116K]

Answer:

P(57

P(-0.67

P(-0.67

Step-by-step explanation:

Previous concepts

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

The Z-score is "a numerical measurement used in statistics of a value's relationship to the mean (average) of a group of values, measured in terms of standard deviations from the mean".  

Solution to the problem

Let X the random variable that represent the lifetime for a TV of a population, and for this case we know the distribution for X is given by:

X \sim N(61,6)  

Where \mu=61 and \sigma=6

We are interested on this probability

P(57

And the best way to solve this problem is using the normal standard distribution and the z score given by:

z=\frac{x-\mu}{\sigma}

If we apply this formula to our probability we got this:

P(57

And we can find this probability like this:

P(-0.67

And in order to find these probabilities we can use tables for the normal standard distribution, excel or a calculator.  

P(-0.67

6 0
3 years ago
Solve K/2 + 5 - 2k = 6k
pantera1 [17]

Answer:

k = 2/3 is the answer!

Step-by-step explanation:

can you mark me branliest please

4 0
3 years ago
Giá trị x thoả mãn x(x − 3) + x − 3 =0 là
svet-max [94.6K]

Here we will use the trial and error method.

  • We will try putting different values of x.
<h3 /><h3>1st of all</h3><h3>x=1</h3>

\begin{gathered}\\ \sf\longmapsto 1(1-3)+1-3=0\end{gathered}

\begin{gathered}\\ \sf\longmapsto (-2)+1-3=0\end{gathered}

\begin{gathered}\\ \sf\longmapsto -2+1-3=0\end{gathered}

\begin{gathered}\\ \sf\longmapsto -2-2=0\end{gathered}

\begin{gathered}\\ \sf\longmapsto -4≠0\end{gathered}

<h2>Now,</h2><h3>x=2</h3>

\begin{gathered}\\ \sf\longmapsto 2(2-3)+2-3=0\end{gathered}

\begin{gathered}\\ \sf\longmapsto 2(-1)+2-3=0\end{gathered}

\begin{gathered}\\ \sf\longmapsto -2+2-3=0\end{gathered}

\begin{gathered}\\ \sf\longmapsto -3≠0\end{gathered}

<h2>Again,</h2><h3>x=3</h3>

\begin{gathered}\\ \sf\longmapsto 3(3-3)+3-3=0\end{gathered}

\begin{gathered}\\ \sf\longmapsto 3(3-3)=0\end{gathered}

\begin{gathered}\\ \sf\longmapsto 3×0=0\end{gathered}

\begin{gathered}\\ \sf\longmapsto 0=0\end{gathered}

<h3>☣Hence, The value of X as 3 satisfies the equation!</h3>
5 0
3 years ago
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